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QuestionA kid speeds up from 2 m/s2 \mathrm{~m/s} to 4 m/s4 \mathrm{~m/s} in 2 seconds. Find the acceleration rate.

Studdy Solution

STEP 1

Assumptions1. The initial velocity of the kid is  m/s \mathrm{~m/s} . The final velocity of the kid is 4 m/s4 \mathrm{~m/s}
3. The time taken to change the velocity is seconds4. We need to find the acceleration, which is the rate of change of velocity

STEP 2

The formula for acceleration is given by the change in velocity divided by the time taken for this change.Acceleration=Final velocity−Initial velocityTimeAcceleration = \frac{Final\, velocity - Initial\, velocity}{Time}

STEP 3

Now, plug in the given values for the final velocity, initial velocity, and time into the formula.
Acceleration= m/s−2 m/s2 sAcceleration = \frac{ \mathrm{~m/s} -2 \mathrm{~m/s}}{2 \mathrm{~s}}

STEP 4

Calculate the change in velocity.
Change in velocity=4 m/s−2 m/s=2 m/sChange\, in\, velocity =4 \mathrm{~m/s} -2 \mathrm{~m/s} =2 \mathrm{~m/s}

STEP 5

Substitute the change in velocity back into the acceleration formula.
Acceleration=2 m/s2 sAcceleration = \frac{2 \mathrm{~m/s}}{2 \mathrm{~s}}

STEP 6

Calculate the acceleration.
Acceleration=2 m/s2 s=1 m/s2Acceleration = \frac{2 \mathrm{~m/s}}{2 \mathrm{~s}} =1 \mathrm{~m/s^2}The kid's rate of acceleration is 1 m/s21 \mathrm{~m/s^2}.

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