QuestionA group of data items and their mean are given. a. Find the deviation from the mean for each of the data items. b. Find the sum of the deviations in part (a). a. Type the deviation from the mean for each of the data items. \begin{tabular}{|c|c|c|c|c|c|} \hline 21 & 35 & 49 & 84 & 126 & 189 \\ \hline & & & & & \\ \hline \end{tabular} b. The sum of the deviations in part (a) is
Studdy Solution
STEP 1
What is this asking?
We're given a set of numbers and their average, and we need to find how far each number is from the average, and then add up all those distances!
Watch out!
Remember that deviations can be positive or negative!
Don't mix up the mean with other statistical measures like median or mode.
STEP 2
1. Calculate the Deviations
2. Sum the Deviations
STEP 3
Alright, let's **calculate the deviation** for each data item.
Remember, the deviation is just the difference between the data item and the mean.
Our **mean** is .
STEP 4
For , the deviation is .
It's negative because is smaller than the mean.
STEP 5
For , the deviation is .
Still negative!
STEP 6
For , the deviation is .
Getting closer to zero!
STEP 7
For , the deviation is .
Makes sense, since *is* the mean!
STEP 8
For , the deviation is .
Now we're positive!
STEP 9
For , the deviation is .
Way bigger than the mean!
STEP 10
Now, let's **add up all those deviations** we just calculated.
This will tell us how spread out the data is overall.
STEP 11
.
Remember, adding a negative number is the same as subtracting its positive counterpart.
STEP 12
Let's group the negative numbers and the positive numbers: .
This makes it easier to see what's going on.
STEP 13
.
Wow! The **sum of the deviations is zero**!
STEP 14
a. The deviations are . b. The sum of the deviations is .
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