QuestionA golf ball is hit at 130 ft/s at $45^{\circ}$ . Find height $h$ after 250 ft using $h(x)=\frac{-32 x^{2}}{130^{2}}+x$ .

Studdy Solution

STEP 1

Assumptions1. The initial velocity of the golf ball is130 feet per second. The golf ball is hit at an inclination of $45^{\circ}$ to the horizontal3. The height $h$ of the golf ball is given by the function $h(x)=\frac{-32 x^{}}{130^{}}+x$
4. The horizontal distance that the golf ball has traveled is represented by $x$
5. We are asked to find the height after the golf ball has traveled250 feet

STEP 2

We can find the height of the golf ball after it has traveled250 feet by substituting $x =250$ into the given function.
$h(250)=\frac{-32 (250)^{2}}{130^{2}}+250$

STEP 3

Now, we need to calculate the value of the expression.
$h(250)=\frac{-32 (62500)}{16900}+250$

STEP 4

Continue to simplify the expression.
$h(250)=\frac{-2000000}{16900}+250$

STEP 5

Divide $-2000000$ by $16900$ .
$h(250)=-118.34+250$

STEP 6

Finally, add $-118.34$ and $250$ to get the height of the golf ball after it has traveled250 feet.
$h(250)=131.66$ So, the height of the golf ball after it has traveled250 feet is approximately $131.66$ feet.

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QuestionA golf ball is hit at 130 ft/s at $45^{\circ}$ . Find height $h$ after 250 ft using $h(x)=\frac{-32 x^{2}}{130^{2}}+x$ .

Studdy Solution

STEP 1

STEP 2

We can find the height of the golf ball after it has traveled250 feet by substituting $x =250$ into the given function.
$h(250)=\frac{-32 (250)^{2}}{130^{2}}+250$

STEP 3

Now, we need to calculate the value of the expression.
$h(250)=\frac{-32 (62500)}{16900}+250$

STEP 4

Continue to simplify the expression.
$h(250)=\frac{-2000000}{16900}+250$

STEP 5

Divide $-2000000$ by $16900$ .
$h(250)=-118.34+250$

STEP 6

Finally, add $-118.34$ and $250$ to get the height of the golf ball after it has traveled250 feet.
$h(250)=131.66$ So, the height of the golf ball after it has traveled250 feet is approximately $131.66$ feet.

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QuestionA golf ball is hit at 130 ft/s at 45∘45^{\circ}45∘. Find height hhh after 250 ft using h(x)=−32x21302+xh(x)=\frac{-32 x^{2}}{130^{2}}+xh(x)=1302−32x2​+x.

Studdy Solution

STEP 1

STEP 2

We can find the height of the golf ball after it has traveled250 feet by substituting x=250x =250x=250 into the given function.h(250)=−32(250)21302+250h(250)=\frac{-32 (250)^{2}}{130^{2}}+250h(250)=1302−32(250)2​+250

STEP 3

Now, we need to calculate the value of the expression.h(250)=−32(62500)16900+250h(250)=\frac{-32 (62500)}{16900}+250h(250)=16900−32(62500)​+250

STEP 4

Continue to simplify the expression.h(250)=−200000016900+250h(250)=\frac{-2000000}{16900}+250h(250)=16900−2000000​+250

STEP 5

Divide −2000000-2000000−2000000 by 169001690016900.h(250)=−118.34+250h(250)=-118.34+250h(250)=−118.34+250

STEP 6

Finally, add −118.34-118.34−118.34 and 250250250 to get the height of the golf ball after it has traveled250 feet.h(250)=131.66h(250)=131.66h(250)=131.66So, the height of the golf ball after it has traveled250 feet is approximately 131.66131.66131.66 feet.

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QuestionA golf ball is hit at 130 ft/s at $45^{\circ}$ . Find height $h$ after 250 ft using $h(x)=\frac{-32 x^{2}}{130^{2}}+x$ .

We can find the height of the golf ball after it has traveled250 feet by substituting $x =250$ into the given function.
$h(250)=\frac{-32 (250)^{2}}{130^{2}}+250$

Now, we need to calculate the value of the expression.
$h(250)=\frac{-32 (62500)}{16900}+250$

Continue to simplify the expression.
$h(250)=\frac{-2000000}{16900}+250$

Divide $-2000000$ by $16900$ .
$h(250)=-118.34+250$

Finally, add $-118.34$ and $250$ to get the height of the golf ball after it has traveled250 feet.
$h(250)=131.66$ So, the height of the golf ball after it has traveled250 feet is approximately $131.66$ feet.