Math  /  Numbers & Operations

QuestionA family left for an overseas holiday on Saturday, June 24. \begin{tabular}{|l|l|l|l|l|l|l|l|} \hline \multicolumn{7}{|c|}{ JUNE } \\ \hline SUN & \multicolumn{2}{|c|}{ MON } & TUE & WED & THU & FRI & SAT \\ \hline 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline 11 & 12 & 13 & 14 & 15 & 16 & 17 \\ \hline 18 & 19 & 20 & 21 & 22 & 23 & 24 \\ \hline 25 & 26 & 27 & 28 & 29 & 30 & \\ \hline \end{tabular}
The family returned home exactly 2 weeks later. What date did they return home?

Studdy Solution

STEP 1

1. The family left on Saturday, June 24.
2. The family returned exactly 2 weeks later, which is equivalent to 14 days.

STEP 2

1. Determine the date 7 days after June 24.
2. Determine the date 14 days after June 24.

STEP 3

Calculate the date one week (7 days) after June 24.
June 24+7 days=July 1 \text{June 24} + 7 \text{ days} = \text{July 1}

STEP 4

Calculate the date two weeks (14 days) after June 24.
June 24+14 days=July 8 \text{June 24} + 14 \text{ days} = \text{July 8}
Therefore, the family returned home on July 8.

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