Math

QuestionCalculate A=sin245tan45+2cos45A = \sin^2 45^\circ - \tan 45^\circ + \sqrt{2} \cos 45^\circ and B=(2i)2(4i1)B = (2-i)^2(4i-1).

Studdy Solution

STEP 1

Assumptions1. We know the trigonometric values for45 degrees. . We understand the operations of addition, subtraction, multiplication, and square roots.
3. We understand the operations with complex numbers.

STEP 2

First, we need to simplify the expression A. We start by replacing the trigonometric values for45 degrees.
A=sin245tan45+2cos45A=\sin ^{2}45^{\circ}-\tan45^{\circ}+\sqrt{2} \cos45^{\circ}

STEP 3

We know that sin45=cos45=12\sin45^{\circ} = \cos45^{\circ} = \frac{1}{\sqrt{2}} and tan45=1\tan45^{\circ} =1. So we substitute these values into the expression.
A=(12)21+212A=\left(\frac{1}{\sqrt{2}}\right)^{2}-1+\sqrt{2} \cdot \frac{1}{\sqrt{2}}

STEP 4

Now, we simplify the expression.
A=121+1A=\frac{1}{2}-1+1

STEP 5

Further simplify the expression.
A=12A=\frac{1}{2}

STEP 6

Now, we need to simplify the expression B. We start by expanding the expression.
B=(2i)2(4i1)B=(2-i)^{2}(4 i-1)

STEP 7

Expand the square in the expression.
B=(44i+i2)(4i1)B=(4-4i+i^{2})(4i-1)

STEP 8

We know that i2=1i^{2} = -1. So we substitute this value into the expression.
B=(44i1)(4i1)B=(4-4i-1)(4i-1)

STEP 9

Further simplify the expression.
B=(34i)(4i)B=(3-4i)(4i-)

STEP 10

Now, we distribute the multiplication across the terms.
B=12i316i2+4iB=12i-3-16i^{2}+4i

STEP 11

Again, we know that i=i^{} = -. So we substitute this value into the expression.
B=i316()+4iB=i-3-16(-)+4i

STEP 12

Further simplify the expression.
B=16+16iB=16+16i-

STEP 13

Finally, simplify the expression.
B=13+16iB=13+16iSo, the solutions are A=2A=\frac{}{2} and B=13+16iB=13+16i.

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