Math

QuestionFind the cost of hardwood floors for a cube room with volume 6,859ft36,859 \mathrm{ft}^{3} at $10\$ 10 per square foot.

Studdy Solution

STEP 1

Assumptions1. The room is a cube with volume 6,859ft36,859 ft^{3} . The contractor charges $10 per square foot for hardwood floors

STEP 2

First, we need to find the area of the floor. Since the room is a cube, the area of one face (or the floor) is the square root of the volume.
Area=VolumeArea = \sqrt[]{Volume}

STEP 3

Now, plug in the given value for the volume to calculate the area.
Area=6,859ft33Area = \sqrt[3]{6,859 ft^{3}}

STEP 4

Calculate the area of the floor.
Area=6,859ft33=19ft2Area = \sqrt[3]{6,859 ft^{3}} =19 ft^{2}

STEP 5

Now that we have the area of the floor, we can find the total cost of the hardwood floors by multiplying the area by the cost per square foot.
Cost=Area×CostpersquarefootCost = Area \times Cost\, per\, square\, foot

STEP 6

Plug in the values for the area and the cost per square foot to calculate the cost.
Cost=19ft2×$10Cost =19 ft^{2} \times \$10

STEP 7

Calculate the cost of the hardwood floors.
Cost=19ft2×$10=$190Cost =19 ft^{2} \times \$10 = \$190The hardwood floors will cost $190.

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