Math  /  Discrete

QuestionA coordinator will select 8 songs from a list of 9 songs to compose an event's musical entertainment lineup. How many different lineups are possible?
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Studdy Solution

STEP 1

What is this asking? How many different ways can we pick 8 songs out of 9 to make a playlist, where the order of the songs matters? Watch out! The order of songs *does* matter here, so it's not a simple combination!
We're talking about a *lineup*, which means the order makes a difference.

STEP 2

1. Permutations

STEP 3

We're looking for the number of *permutations*, which means how many ways we can arrange a smaller group from a larger group, where order matters.
Think of it like picking the first song, then the second, and so on.

STEP 4

We have 9 choices for the first song.
After picking that one, we have 8 choices left for the second song.
Then 7 choices for the third, and so on, until we've picked 8 songs.

STEP 5

To get the **total number of lineups**, we **multiply** these numbers together.
This is because each choice of the first song can be paired with any choice of the second song, and so on.
This gives us 987654329 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2.
This is called a *permutation*.

STEP 6

We can write this using the **permutation formula**: P(n,k)=n!(nk)!P(n, k) = \frac{n!}{(n-k)!}, where nn is the **total number of songs** and kk is the **number of songs we're choosing**.
In our case, n=9n = 9 and k=8k = 8.

STEP 7

Let's **plug in the numbers**: P(9,8)=9!(98)!=9!1!=9!P(9, 8) = \frac{9!}{(9-8)!} = \frac{9!}{1!} = 9!.

STEP 8

9!=987654321=362,8809! = 9 \cdot 8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2 \cdot 1 = \textbf{362,880}.

STEP 9

There are a whopping **362,880** different possible lineups!

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