Math

QuestionFind the equation of a circle with center at the origin and radius 12\frac{1}{2}. Options: A. x2+y2=14x^{2}+y^{2}=\frac{1}{4} B. x2+y2=12x^{2}+y^{2}=\frac{1}{2} C. x2+y2=1x^{2}+y^{2}=1 D. x2+y2=2x^{2}+y^{2}=2

Studdy Solution

STEP 1

Assumptions1. The circle is centered at the origin (0,0) . The radius of the circle is 1\frac{1}{}

STEP 2

The general equation for a circle centered at the origin is given byx2+y2=r2x^{2}+y^{2}=r^{2}where rr is the radius of the circle.

STEP 3

Substitute the given radius into the equation of the circle.
x2+y2=(12)2x^{2}+y^{2}=\left(\frac{1}{2}\right)^{2}

STEP 4

Calculate the square of the radius.
x2+y2=14x^{2}+y^{2}=\frac{1}{4}So, the equation of the circle is x2+y2=14x^{2}+y^{2}=\frac{1}{4}. Therefore, the correct answer is option A.

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