QuestionCalculate the average volume of pollutants from three plants: 48.7 L, 0.86 L, and 0.788 L. Report with correct significant digits.

Studdy Solution

STEP 1

Assumptions1. The volumes of pollutant produced by each plant are as follows - New Bedford48.7 L - Pitt0.86 L - Doheny0.788 L. The average volume is calculated by summing the volumes produced by each plant and dividing by the number of plants.
3. The number of significant digits in the average volume should match the number of significant digits in the least precise measurement.

STEP 2

First, we need to sum the volumes of pollutant produced by each plant.
$Total\, volume = Volume_{New\, Bedford} + Volume_{itt} + Volume_{oheny}$

STEP 3

Now, plug in the given values for the volumes produced by each plant to calculate the total volume.
$Total\, volume =48.7\, L +0.86\, L +0.788\, L$

STEP 4

Calculate the total volume of pollutant produced.
$Total\, volume =48.7\, L +0.86\, L +0.788\, L =50.348\, L$

STEP 5

Now that we have the total volume, we can find the average volume by dividing the total volume by the number of plants (3).
$Average\, volume = Total\, volume / Number\, of\, plants$

STEP 6

Plug in the values for the total volume and the number of plants to calculate the average volume.
$Average\, volume =50.348\, L /3$

STEP 7

Calculate the average volume of pollutant produced.
$Average\, volume =50.348\, L /3 =16.78266667\, L$

STEP 8

The number of significant digits in our answer should match the number of significant digits in our least precise measurement. The least precise measurement is the volume produced by the Pitt plant, which has two significant digits. Therefore, we should round our answer to two significant digits.
$Average\, volume =17\, L$ The chemical engineer should report an average volume of17 L.

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