Math

QuestionCalculate the average volume of pollutant from the plants: Platte (7.08 L), New Bedford (0.901 L), Doheny (3.107 L).

Studdy Solution

STEP 1

Assumptions1. The volume of pollutant produced by the Platte plant is7.08 L. The volume of pollutant produced by the New Bedford plant is0.901 L3. The volume of pollutant produced by the Doheny plant is3.107 L4. The average volume of pollutant is calculated as the sum of the volumes produced by each plant divided by the number of plants.

STEP 2

First, we need to find the total volume of pollutant produced by all the plants. We can do this by adding up the volumes produced by each plant.
Totalvolume=VolumePlatte+VolumeNewBedford+VolumeohenyTotal\, volume = Volume_{Platte} + Volume_{New\, Bedford} + Volume_{oheny}

STEP 3

Now, plug in the given values for the volumes produced by each plant to calculate the total volume.
Totalvolume=7.08L+0.901L+3.107LTotal\, volume =7.08\, L +0.901\, L +3.107\, L

STEP 4

Calculate the total volume of pollutant produced by all the plants.
Totalvolume=7.08L+0.901L+3.107L=11.088LTotal\, volume =7.08\, L +0.901\, L +3.107\, L =11.088\, L

STEP 5

Now that we have the total volume of pollutant, we can find the average volume produced by each plant. This is calculated by dividing the total volume by the number of plants.
Averagevolume=Totalvolume/NumberofplantsAverage\, volume = Total\, volume / Number\, of\, plants

STEP 6

Plug in the values for the total volume and the number of plants to calculate the average volume.
Averagevolume=11.088L/3Average\, volume =11.088\, L /3

STEP 7

Calculate the average volume of pollutant produced by each plant.
Averagevolume=11.088L/3=3.696LAverage\, volume =11.088\, L /3 =3.696\, LHowever, we need to ensure that our answer has the correct number of significant digits. The number with the least number of decimal places in the problem is7.08, which has two decimal places. Therefore, our answer should also have two decimal places.

STEP 8

Round the average volume to two decimal places.
Averagevolume=3.70LAverage\, volume =3.70\, LThe chemical engineer should report an average volume of3.70 L.

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