Math  /  Algebra

Question2
A cat adoption facility takes in an average of 6 cats per day. The facility has to keep their cat occupancy below 300 . Currently, the facility has 252 cats. If none of their cals get adopted, how many more days, xx, can the facility continue to take in cats?

Studdy Solution

STEP 1

1. The facility takes in an average of 6 cats per day.
2. The facility must keep the cat occupancy below 300.
3. Currently, the facility has 252 cats.
4. No cats are being adopted during this period.
5. We need to find the number of days, x x , the facility can continue to take in cats without exceeding the occupancy limit.

STEP 2

1. Define the problem using an equation.
2. Solve the equation for x x .

STEP 3

Define the problem using an equation.
Let x x be the number of days the facility can continue to take in cats without exceeding the occupancy limit.
The total number of cats after x x days is given by: 252+6x<300 252 + 6x < 300

STEP 4

Solve the equation for x x .
Subtract 252 from both sides to isolate the term with x x : 6x<300252 6x < 300 - 252 6x<48 6x < 48
Divide both sides by 6 to solve for x x : x<486 x < \frac{48}{6} x<8 x < 8
The facility can continue to take in cats for up to 7 full days without exceeding the occupancy limit.

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