QuestionA clock business has fixed costs of \ $7000. Find the average cost per clock for$ x=100, 1000, 10,000 $:$ \frac{0.4x + 7000}{x}$.

Studdy Solution

STEP 1

Assumptions1. The weekly fixed costs are $7000. The average cost per clock for the business to manufacture$ x $clocks is described by the function$ \frac{0.4x +7000}{x} $<br />3. We need to find the average cost when$ x=100,1000 $, and$ 10,000$

STEP 2

First, let's find the average cost when $x=100$ . We can do this by substituting $x=100$ into the given function.
$Average\, cost = \frac{0.4 \times100 +7000}{100}$

STEP 3

Calculate the average cost when $x=100$ .
$Average\, cost = \frac{40 +7000}{100} = \$70.40$

STEP 4

Next, let's find the average cost when $x=1000$ . We can do this by substituting $x=1000$ into the given function.
$Average\, cost = \frac{0.4 \times1000 +7000}{1000}$

STEP 5

Calculate the average cost when $x=1000$ .
$Average\, cost = \frac{400 +7000}{1000} = \$7.40$

STEP 6

Finally, let's find the average cost when $x=10,000$ . We can do this by substituting $x=10,000$ into the given function.
$Average\, cost = \frac{0.4 \times10,000 +7000}{10,000}$

STEP 7

Calculate the average cost when $x=10,000$ .
$Average\, cost = \frac{4000 +7000}{10,000} = \$1.10$ The average cost when manufacturing100 clocks is $70.40 per clock, when manufacturing1000 clocks it's$ 7.40 per clock, and when manufacturing10,000 clocks it's $1.10 per clock.

Was this helpful?

QuestionA clock business has fixed costs of \ $7000. Find the average cost per clock for$ x=100, 1000, 10,000 $:$ \frac{0.4x + 7000}{x}$.

Studdy Solution

STEP 1

Assumptions1. The weekly fixed costs are $7000. The average cost per clock for the business to manufacture$ x $clocks is described by the function$ \frac{0.4x +7000}{x} $<br />3. We need to find the average cost when$ x=100,1000 $, and$ 10,000$

STEP 2

First, let's find the average cost when $x=100$ . We can do this by substituting $x=100$ into the given function.
$Average\, cost = \frac{0.4 \times100 +7000}{100}$

STEP 3

Calculate the average cost when $x=100$ .
$Average\, cost = \frac{40 +7000}{100} = \$70.40$

STEP 4

Next, let's find the average cost when $x=1000$ . We can do this by substituting $x=1000$ into the given function.
$Average\, cost = \frac{0.4 \times1000 +7000}{1000}$

STEP 5

Calculate the average cost when $x=1000$ .
$Average\, cost = \frac{400 +7000}{1000} = \$7.40$

STEP 6

Finally, let's find the average cost when $x=10,000$ . We can do this by substituting $x=10,000$ into the given function.
$Average\, cost = \frac{0.4 \times10,000 +7000}{10,000}$

STEP 7

Calculate the average cost when $x=10,000$ .
$Average\, cost = \frac{4000 +7000}{10,000} = \$1.10$ The average cost when manufacturing100 clocks is $70.40 per clock, when manufacturing1000 clocks it's$ 7.40 per clock, and when manufacturing10,000 clocks it's $1.10 per clock.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionA clock business has fixed costs of \7000.Findtheaveragecostperclockfor7000. Find the average cost per clock for 7000.Findtheaveragecostperclockforx=100, 1000, 10,000:: :\frac{0.4x + 7000}{x}$.

Studdy Solution

STEP 1

STEP 2

First, let's find the average cost when x=100x=100x=100. We can do this by substituting x=100x=100x=100 into the given function.Average cost=0.4×100+7000100Average\, cost = \frac{0.4 \times100 +7000}{100}Averagecost=1000.4×100+7000​

STEP 3

Calculate the average cost when x=100x=100x=100.Average cost=40+7000100=$70.40Average\, cost = \frac{40 +7000}{100} = \$70.40Averagecost=10040+7000​=$70.40

STEP 4

Next, let's find the average cost when x=1000x=1000x=1000. We can do this by substituting x=1000x=1000x=1000 into the given function.Average cost=0.4×1000+70001000Average\, cost = \frac{0.4 \times1000 +7000}{1000}Averagecost=10000.4×1000+7000​

STEP 5

Calculate the average cost when x=1000x=1000x=1000.Average cost=400+70001000=$7.40Average\, cost = \frac{400 +7000}{1000} = \$7.40Averagecost=1000400+7000​=$7.40

STEP 6

Finally, let's find the average cost when x=10,000x=10,000x=10,000. We can do this by substituting x=10,000x=10,000x=10,000 into the given function.Average cost=0.4×10,000+700010,000Average\, cost = \frac{0.4 \times10,000 +7000}{10,000}Averagecost=10,0000.4×10,000+7000​

STEP 7

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionA clock business has fixed costs of \ $7000. Find the average cost per clock for$ x=100, 1000, 10,000 $:$ \frac{0.4x + 7000}{x}$.

First, let's find the average cost when $x=100$ . We can do this by substituting $x=100$ into the given function.
$Average\, cost = \frac{0.4 \times100 +7000}{100}$

Calculate the average cost when $x=100$ .
$Average\, cost = \frac{40 +7000}{100} = \$70.40$

Next, let's find the average cost when $x=1000$ . We can do this by substituting $x=1000$ into the given function.
$Average\, cost = \frac{0.4 \times1000 +7000}{1000}$

Calculate the average cost when $x=1000$ .
$Average\, cost = \frac{400 +7000}{1000} = \$7.40$

Finally, let's find the average cost when $x=10,000$ . We can do this by substituting $x=10,000$ into the given function.
$Average\, cost = \frac{0.4 \times10,000 +7000}{10,000}$