QuestionA bullet has 14.6 g lead, 0.1 g tin, and 0.8 g antimony. Find the percentage of tin in the bullet, rounded to the ones place.

Studdy Solution

STEP 1

Assumptions1. The bullet contains14.6g of lead. The bullet contains0.1g of tin3. The bullet contains0.8g of antimony4. We are asked to find the percentage of tin in the bullet

STEP 2

First, we need to find the total weight of the bullet. This can be done by adding the weights of the three metals.
$Total\, weight = Weight\, of\, lead + Weight\, of\, tin + Weight\, of\, antimony$

STEP 3

Now, plug in the given values for the weights of the three metals to calculate the total weight.
$Total\, weight =14.6\, g +0.1\, g +0.8\, g$

STEP 4

Calculate the total weight of the bullet.
$Total\, weight =14.6\, g +0.1\, g +0.8\, g =15.\, g$

STEP 5

Now that we have the total weight of the bullet, we can find the percentage of tin in the bullet. This can be done by dividing the weight of tin by the total weight and then multiplying by100.
$Percentage\, of\, tin = \left(\frac{Weight\, of\, tin}{Total\, weight}\right) \times100$

STEP 6

Plug in the values for the weight of tin and the total weight to calculate the percentage of tin.
$Percentage\, of\, tin = \left(\frac{0.1\, g}{15.5\, g}\right) \times100$

STEP 7

Calculate the percentage of tin in the bullet.
$Percentage\, of\, tin = \left(\frac{0.1\, g}{15.5\, g}\right) \times100 =0.64516129\%$

STEP 8

Round the percentage of tin to the ones place.
$Percentage\, of\, tin =0.6\%$ The percentage of tin in the bullet is0.6%.

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