QuestionA boulder falls for 7 seconds. How far did it fall? Use the formula for distance: $d = \frac{1}{2}gt^2$ .

Studdy Solution

STEP 1

Assumptions1. The boulder falls freely under the influence of gravity. . The acceleration due to gravity is approximately9.8 m/s².
3. The initial velocity of the boulder is0 m/s (it starts from rest).
4. The time of fall is7 seconds.
5. We ignore air resistance.

STEP 2

We can use the equation of motion that relates distance (s), initial velocity (u), acceleration (a), and time (t):
$s = ut + \frac{1}{2}at^2$

STEP 3

Plug in the given values for the initial velocity (u =0 m/s), acceleration (a =9.8 m/s²), and time (t =7 s) to calculate the distance.
$s =0 \times7 + \frac{1}{2} \times9.8 \times (7)^2$

STEP 4

implify the equation.
$s =0 + \frac{1}{2} \times9.8 \times49$

STEP 5

Calculate the distance.
$s = \frac{1}{2} \times9.8 \times49 =240.1 \, m$ The boulder fell approximately240.1 meters.

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QuestionA boulder falls for 7 seconds. How far did it fall? Use the formula for distance: $d = \frac{1}{2}gt^2$ .

Studdy Solution

STEP 1

Assumptions1. The boulder falls freely under the influence of gravity. . The acceleration due to gravity is approximately9.8 m/s².
3. The initial velocity of the boulder is0 m/s (it starts from rest).
4. The time of fall is7 seconds.
5. We ignore air resistance.

STEP 2

We can use the equation of motion that relates distance (s), initial velocity (u), acceleration (a), and time (t):
$s = ut + \frac{1}{2}at^2$

STEP 3

Plug in the given values for the initial velocity (u =0 m/s), acceleration (a =9.8 m/s²), and time (t =7 s) to calculate the distance.
$s =0 \times7 + \frac{1}{2} \times9.8 \times (7)^2$

STEP 4

implify the equation.
$s =0 + \frac{1}{2} \times9.8 \times49$

STEP 5

Calculate the distance.
$s = \frac{1}{2} \times9.8 \times49 =240.1 \, m$ The boulder fell approximately240.1 meters.

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QuestionA boulder falls for 7 seconds. How far did it fall? Use the formula for distance: d=12gt2d = \frac{1}{2}gt^2d=21​gt2.

Studdy Solution

STEP 1

Assumptions1. The boulder falls freely under the influence of gravity. . The acceleration due to gravity is approximately9.8 m/s².3. The initial velocity of the boulder is0 m/s (it starts from rest).4. The time of fall is7 seconds.5. We ignore air resistance.

STEP 2

We can use the equation of motion that relates distance (s), initial velocity (u), acceleration (a), and time (t):s=ut+12at2s = ut + \frac{1}{2}at^2s=ut+21​at2

STEP 3

Plug in the given values for the initial velocity (u =0 m/s), acceleration (a =9.8 m/s²), and time (t =7 s) to calculate the distance.s=0×7+12×9.8×(7)2s =0 \times7 + \frac{1}{2} \times9.8 \times (7)^2s=0×7+21​×9.8×(7)2

STEP 4

implify the equation.s=0+12×9.8×49s =0 + \frac{1}{2} \times9.8 \times49s=0+21​×9.8×49

STEP 5

Calculate the distance.s=12×9.8×49=240.1 ms = \frac{1}{2} \times9.8 \times49 =240.1 \, ms=21​×9.8×49=240.1mThe boulder fell approximately240.1 meters.

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QuestionA boulder falls for 7 seconds. How far did it fall? Use the formula for distance: $d = \frac{1}{2}gt^2$ .

Assumptions1. The boulder falls freely under the influence of gravity. . The acceleration due to gravity is approximately9.8 m/s².
3. The initial velocity of the boulder is0 m/s (it starts from rest).
4. The time of fall is7 seconds.
5. We ignore air resistance.

We can use the equation of motion that relates distance (s), initial velocity (u), acceleration (a), and time (t):
$s = ut + \frac{1}{2}at^2$

Plug in the given values for the initial velocity (u =0 m/s), acceleration (a =9.8 m/s²), and time (t =7 s) to calculate the distance.
$s =0 \times7 + \frac{1}{2} \times9.8 \times (7)^2$

implify the equation.
$s =0 + \frac{1}{2} \times9.8 \times49$

Calculate the distance.
$s = \frac{1}{2} \times9.8 \times49 =240.1 \, m$ The boulder fell approximately240.1 meters.