Math  /  Discrete

Question(A(BC))=(A \cup(B \cap C))=

Studdy Solution

STEP 1

What is this asking? We need to find which parts of the Venn diagram are included in (A(BC))(A \cup (B \cap C)) and add up the numbers in those parts. Watch out! Don't forget that the union symbol (\cup) means "everything in either set" and the intersection symbol (\cap) means "everything in *both* sets".
Don't mix them up!

STEP 2

1. Find the value of BCB \cap C.
2. Find the value of A(BC)A \cup (B \cap C).

STEP 3

Alright, so, BCB \cap C means the parts where *both* BB *and* CC are present.
Looking at our awesome Venn diagram, that's the overlap between the BB and CC circles!

STEP 4

We see the number **9** in the part where *only* BB and CC overlap, and the number **1** where *all three* circles overlap.
Since both of these areas are in both BB and CC, we **add** them together: 9+1=109 + 1 = \mathbf{10}.
So, the value of BCB \cap C is **10**.

STEP 5

Now, we want A(BC)A \cup (B \cap C).
This means *everything* in AA *plus* everything in (BC)(B \cap C), but without double-counting the overlap.
We already figured out that (BC)(B \cap C) has a value of **10** (that's the overlap of BB and CC).

STEP 6

AA includes the sections with **14** (only AA), **8** (overlap of AA and BB), **6** (overlap of AA and CC), and **1** (overlap of all three).
Adding those up: 14+8+6+1=2914 + 8 + 6 + 1 = \mathbf{29}.

STEP 7

Now, let's combine that with our value for (BC)(B \cap C), which is **10**.
We have A=29A = 29 and (BC)=10(B \cap C) = 10.
We want A(BC)A \cup (B \cap C).
Notice that the overlap of AA and (BC)(B \cap C) is already included in our sum for AA (specifically, the **6** and the **1**).
So, the parts of (BC)(B \cap C) that aren't already counted in AA is just the part where *only* BB and CC overlap, which is **9**.

STEP 8

Therefore, A(BC)A \cup (B \cap C) is 2929 (all of AA) plus the part of (BC)(B \cap C) that we haven't counted yet, which is 99.
So, 29+(10(1+6))=29+(107)=29+3=3229 + (10 - (1+6)) = 29 + (10 - 7) = 29 + 3 = \mathbf{32}.

STEP 9

The value of (A(BC))(A \cup (B \cap C)) is **32**.

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