Math

QuestionFind the probability of either event AA or event BB occurring, given P(A)=0.22P(A)=0.22 and P(B)=0.42P(B)=0.42.

Studdy Solution

STEP 1

Assumptions1. Events AA and BB are mutually exclusive. This means that they cannot both occur at the same time. If one event occurs, the other cannot. . The probability of event AA occurring, (A)(A), is0.22.
3. The probability of event BB occurring, (B)(B), is0.42.

STEP 2

For mutually exclusive events, the probability of either event AA OR event BB occurring is the sum of their individual probabilities. This can be represented mathematically as(AORB)=(A)+(B)(A \, OR \, B) =(A) +(B)

STEP 3

Now, plug in the given values for (A)(A) and (B)(B) to calculate (A(A OR B)B).
(AORB)=0.22+0.42(A \, OR \, B) =0.22 +0.42

STEP 4

Calculate the probability of either event AA OR event BB occurring.
(AORB)=0.22+0.42=0.64(A \, OR \, B) =0.22 +0.42 =0.64So, the probability of either event AA OR event BB occurring is0.64.

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