Question9. What subatomic particles are in an ion with atomic number 52, mass number $\mathbf{1 1 0}$ and a charge of 4+?
10. What subatomic particles are in a nitride ion if it has a mass number of $\mathbf{2 0 ?}$ \# $\mathrm{p}^{+}$ : \# of protons? $\# \mathrm{n}^{0}$ : \# $\mathrm{e}^{-}$ : : \# $\mathrm{p}^{+}$ : $\# \mathrm{n}^{0}$ : \# $\mathrm{e}^{-}$ : \# of neutrons? \# of electrons? \# of protons? \# of neutrons? \# of electrons?

Studdy Solution

STEP 1

1. The atomic number represents the number of protons in an atom.
2. The mass number is the sum of protons and neutrons in an atom.
3. The charge of an ion is determined by the difference between the number of protons and electrons.
4. A nitride ion is formed from nitrogen, which has an atomic number of 7.

STEP 2

1. Determine the number of protons, neutrons, and electrons for the ion with atomic number 52 and mass number 110.
2. Determine the number of protons, neutrons, and electrons for the nitride ion with a mass number of 20.

STEP 3

For the ion with atomic number 52: - The number of protons ( $\# \mathrm{p}^{+}$ ) is equal to the atomic number, which is 52.

STEP 4

For the ion with mass number 110: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $110 - 52 = 58$ .

STEP 5

For the ion with a charge of 4+: - The number of electrons ( $\# \mathrm{e}^{-}$ ) is the number of protons minus the charge: $52 - 4 = 48$ .

STEP 6

For the nitride ion: - The atomic number of nitrogen is 7, so the number of protons ( $\# \mathrm{p}^{+}$ ) is 7.

STEP 7

For the nitride ion with mass number 20: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $20 - 7 = 13$ .

STEP 8

For a nitride ion ( $\mathrm{N}^{3-}$ ): - The number of electrons ( $\# \mathrm{e}^{-}$ ) is the number of protons plus 3 (because it has a 3- charge): $7 + 3 = 10$ .
The subatomic particles for each ion are:
For the ion with atomic number 52 and mass number 110: - $\# \mathrm{p}^{+} = 52$ - $\# \mathrm{n}^{0} = 58$ - $\# \mathrm{e}^{-} = 48$
For the nitride ion with mass number 20: - $\# \mathrm{p}^{+} = 7$ - $\# \mathrm{n}^{0} = 13$ - $\# \mathrm{e}^{-} = 10$

Was this helpful?

Studdy Solution

STEP 1

STEP 2

1. Determine the number of protons, neutrons, and electrons for the ion with atomic number 52 and mass number 110.
2. Determine the number of protons, neutrons, and electrons for the nitride ion with a mass number of 20.

STEP 3

For the ion with atomic number 52: - The number of protons ( $\# \mathrm{p}^{+}$ ) is equal to the atomic number, which is 52.

STEP 4

For the ion with mass number 110: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $110 - 52 = 58$ .

STEP 5

For the ion with a charge of 4+: - The number of electrons ( $\# \mathrm{e}^{-}$ ) is the number of protons minus the charge: $52 - 4 = 48$ .

STEP 6

For the nitride ion: - The atomic number of nitrogen is 7, so the number of protons ( $\# \mathrm{p}^{+}$ ) is 7.

STEP 7

For the nitride ion with mass number 20: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $20 - 7 = 13$ .

STEP 8

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Studdy Solution

STEP 1

STEP 2

1. Determine the number of protons, neutrons, and electrons for the ion with atomic number 52 and mass number 110.2. Determine the number of protons, neutrons, and electrons for the nitride ion with a mass number of 20.

STEP 3

For the ion with atomic number 52: - The number of protons (#p+\# \mathrm{p}^{+}#p+) is equal to the atomic number, which is 52.

STEP 4

For the ion with mass number 110: - The number of neutrons (#n0\# \mathrm{n}^{0}#n0) is the mass number minus the number of protons: 110−52=58110 - 52 = 58110−52=58.

STEP 5

For the ion with a charge of 4+: - The number of electrons (#e−\# \mathrm{e}^{-}#e−) is the number of protons minus the charge: 52−4=4852 - 4 = 4852−4=48.

STEP 6

For the nitride ion: - The atomic number of nitrogen is 7, so the number of protons (#p+\# \mathrm{p}^{+}#p+) is 7.

STEP 7

For the nitride ion with mass number 20: - The number of neutrons (#n0\# \mathrm{n}^{0}#n0) is the mass number minus the number of protons: 20−7=1320 - 7 = 1320−7=13.

STEP 8

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

1. Determine the number of protons, neutrons, and electrons for the ion with atomic number 52 and mass number 110.
2. Determine the number of protons, neutrons, and electrons for the nitride ion with a mass number of 20.

For the ion with atomic number 52: - The number of protons ( $\# \mathrm{p}^{+}$ ) is equal to the atomic number, which is 52.

For the ion with mass number 110: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $110 - 52 = 58$ .

For the ion with a charge of 4+: - The number of electrons ( $\# \mathrm{e}^{-}$ ) is the number of protons minus the charge: $52 - 4 = 48$ .

For the nitride ion: - The atomic number of nitrogen is 7, so the number of protons ( $\# \mathrm{p}^{+}$ ) is 7.

For the nitride ion with mass number 20: - The number of neutrons ( $\# \mathrm{n}^{0}$ ) is the mass number minus the number of protons: $20 - 7 = 13$ .