Math

QuestionCalculate (9+9i)(9+9i)(9+9 i)(\overline{9+9 i}).

Studdy Solution

STEP 1

Assumptions1. We are given a complex number 9+9i9+9i and its conjugate 9+9i\overline{9+9i}. . The conjugate of a complex number a+bia+bi is defined as abia-bi.
3. We need to find the product of the complex number and its conjugate.

STEP 2

First, we need to find the conjugate of the complex number 9+9i9+9i. As per the definition, the conjugate of a complex number a+bia+bi is abia-bi.
9+9i=99i\overline{9+9i} =9 -9i

STEP 3

Now, we need to multiply the complex number 9+9i9+9i with its conjugate 99i9-9i.
(9+9i)(99i)(9+9i)(9-9i)

STEP 4

We will use the distributive property of multiplication over addition to multiply these two complex numbers.
(9+9i)(99i)=9(9)+9(9i)+9i(9)+9i(9i)(9+9i)(9-9i) =9(9) +9(-9i) +9i(9) +9i(-9i)

STEP 5

Now, simplify the multiplication.
=8181i+81i81i2=81 -81i +81i -81i^2

STEP 6

Note that i2i^2 is equal to 1-1. So, replace i2i^2 with 1-1.
=8181(1)=81 -81(-1)

STEP 7

Finally, simplify the expression to get the result.
=81+81=162=81 +81 =162So, (9+9i)(9+9i)=162(9+9i)(\overline{9+9i})=162.

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