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QuestionCalculate the following:
1) 78.08molL×40L=□mol78.08 \frac{\mathrm{mol}}{\mathrm{L}} \times 40 \mathrm{L} = \square \mathrm{mol}
2) 0.93molL×2.025L=□mol0.93 \frac{\mathrm{mol}}{\mathrm{L}} \times 2.025 \mathrm{L} = \square \mathrm{mol}
3) 599.25m÷42.528s=□ms599.25 \mathrm{m} \div 42.528 \mathrm{s} = \square \frac{\mathrm{m}}{\mathrm{s}}

Studdy Solution

STEP 1

Assumptions1. The given quantities are in the correct units for the calculations. . The operations of multiplication and division are to be performed as indicated.

STEP 2

First, we will solve the first equation. This is a multiplication of two quantities.
78.08mol×40L=?mol78.08 \frac{mol}{} \times40 L = ? mol

STEP 3

Perform the multiplication to find the answer.
78.08mol×40L=3123.2mol78.08 \frac{mol}{} \times40 L =3123.2 mol

STEP 4

Next, we will solve the second equation. This is also a multiplication of two quantities.
0.93mol×2.025L=?mol0.93 \frac{mol}{} \times2.025 L = ? mol

STEP 5

Perform the multiplication to find the answer.
0.93mol×2.025L=1.88425mol0.93 \frac{mol}{} \times2.025 L =1.88425 mol

STEP 6

Finally, we will solve the third equation. This is a division of two quantities.
599.25m÷42.528s=?ms599.25 m \div42.528 s = ? \frac{m}{s}

STEP 7

Perform the division to find the answer.
599.25m÷42.528s=14.09ms599.25 m \div42.528 s =14.09 \frac{m}{s}So, the solutions are 3123.2mol3123.2 mol, 1.88425mol1.88425 mol and 14.09ms14.09 \frac{m}{s}.

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