Math

QuestionFactor the expressions: 6x2+48x6 x^{2}+48 x and x249x^{2}-49.

Studdy Solution

STEP 1

Assumptions1. We are given two expressions 6x+48x6x^{}+48x and x49x^{}-49 . We need to factorize these expressions

STEP 2

Let's start with the first expression 6x2+48x6x^{2}+48x. We need to find the greatest common factor (GCF) of the terms in the expression.

STEP 3

The GCF of 6x26x^{2} and 48x48x is 6x6x.

STEP 4

Factor out the GCF from the expression.
6x2+48x=6x(x+8)6x^{2}+48x =6x(x+8)

STEP 5

Now, let's move on to the second expression x249x^{2}-49. This is a difference of squares, which can be factored using the formula a2b2=(ab)(a+b)a^{2}-b^{2} = (a-b)(a+b).

STEP 6

Identify the squares in the expression. Here, a2=x2a^{2} = x^{2} and b2=49b^{2} =49.

STEP 7

Take the square root of a2a^{2} and b2b^{2} to find the values of aa and bb. Here, a=xa = x and b=7b =7.

STEP 8

Substitute the values of aa and bb into the formula to factorize the expression.
x249=(x7)(x+7)x^{2}-49 = (x-7)(x+7)So, the factorized forms of the given expressions are 6x(x+8)6x(x+8) and (x7)(x+7)(x-7)(x+7).

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