Question6. A student forgets to turn off a $6.00 \times 10^{2} \mathrm{~W}$ block heater of a car when the weather turns warm. If 14 h goes by before he shuts it off, how much energy is used by the heater? (Hint....think back to unit 3 energy formulas). (you answer)

Studdy Solution

STEP 1

1. The power of the block heater is constant at $6.00 \times 10^{2}$ watts.
2. The time duration for which the heater is left on is 14 hours.
3. Energy used can be calculated using the formula $\text{Energy} = \text{Power} \times \text{Time}$ .

STEP 2

1. Convert time from hours to seconds.
2. Calculate the energy used by the heater.

STEP 3

First, convert the time from hours to seconds since power is given in watts (joules per second). There are 3600 seconds in an hour:
$\text{Time in seconds} = 14 \, \text{hours} \times 3600 \, \text{seconds/hour}$
$\text{Time in seconds} = 50400 \, \text{seconds}$

STEP 4

Use the energy formula $\text{Energy} = \text{Power} \times \text{Time}$ to calculate the energy used:
$\text{Energy} = 6.00 \times 10^{2} \, \text{W} \times 50400 \, \text{s}$
$\text{Energy} = 3.024 \times 10^{7} \, \text{Joules}$
The energy used by the heater is:
$\boxed{3.024 \times 10^{7} \, \text{Joules}}$

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