QuestionSolve the equation: $5(6 x-2)+9=30 x-1$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $5(6x-)+9=30x-1$ . We need to solve for $x$

STEP 2

First, we need to distribute the5 into the parentheses on the left side of the equation.
$5(6x-2)+9 =56x -52 +9$

STEP 3

Perform the multiplication to simplify the left side of the equation.
$30x -10 +9 =30x -1$

STEP 4

Combine like terms on the left side of the equation.
$30x -1 =30x -1$

STEP 5

Subtract $30x$ from both sides of the equation to isolate $x$ .
$30x -30x -1 =30x -30x -1$

STEP 6

implify both sides of the equation.
$-1 = -1$

STEP 7

Since both sides of the equation are equal, this means that the equation is an identity and is true for all values of $x$ .
The solution is all real numbers.

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QuestionSolve the equation: $5(6 x-2)+9=30 x-1$ .

Studdy Solution

STEP 1

Assumptions1. The given equation is $5(6x-)+9=30x-1$ . We need to solve for $x$

STEP 2

First, we need to distribute the5 into the parentheses on the left side of the equation.
$5(6x-2)+9 =56x -52 +9$

STEP 3

Perform the multiplication to simplify the left side of the equation.
$30x -10 +9 =30x -1$

STEP 4

Combine like terms on the left side of the equation.
$30x -1 =30x -1$

STEP 5

Subtract $30x$ from both sides of the equation to isolate $x$ .
$30x -30x -1 =30x -30x -1$

STEP 6

implify both sides of the equation.
$-1 = -1$

STEP 7

Since both sides of the equation are equal, this means that the equation is an identity and is true for all values of $x$ .
The solution is all real numbers.

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QuestionSolve the equation: 5(6x−2)+9=30x−15(6 x-2)+9=30 x-15(6x−2)+9=30x−1.

Studdy Solution

STEP 1

Assumptions1. The given equation is 5(6x−)+9=30x−15(6x-)+9=30x-15(6x−)+9=30x−1 . We need to solve for xxx

STEP 2

First, we need to distribute the5 into the parentheses on the left side of the equation.5(6x−2)+9=5∗6x−5∗2+95(6x-2)+9 =5*6x -5*2 +95(6x−2)+9=5∗6x−5∗2+9

STEP 3

Perform the multiplication to simplify the left side of the equation.30x−10+9=30x−130x -10 +9 =30x -130x−10+9=30x−1

STEP 4

Combine like terms on the left side of the equation.30x−1=30x−130x -1 =30x -130x−1=30x−1

STEP 5

Subtract 30x30x30x from both sides of the equation to isolate xxx.30x−30x−1=30x−30x−130x -30x -1 =30x -30x -130x−30x−1=30x−30x−1

STEP 6

implify both sides of the equation.−1=−1-1 = -1−1=−1

STEP 7

Since both sides of the equation are equal, this means that the equation is an identity and is true for all values of xxx.The solution is all real numbers.

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionSolve the equation: $5(6 x-2)+9=30 x-1$ .

Assumptions1. The given equation is $5(6x-)+9=30x-1$ . We need to solve for $x$

First, we need to distribute the5 into the parentheses on the left side of the equation.
$5(6x-2)+9 =56x -52 +9$

Perform the multiplication to simplify the left side of the equation.
$30x -10 +9 =30x -1$

Combine like terms on the left side of the equation.
$30x -1 =30x -1$

Subtract $30x$ from both sides of the equation to isolate $x$ .
$30x -30x -1 =30x -30x -1$

implify both sides of the equation.
$-1 = -1$

Since both sides of the equation are equal, this means that the equation is an identity and is true for all values of $x$ .
The solution is all real numbers.