Math  /  Algebra

Question5=5(4n1)35=\frac{5(4 n-1)}{3}

Studdy Solution

STEP 1

1. The equation given is 5=5(4n1)3 5 = \frac{5(4n-1)}{3} .
2. We are solving for the variable n n .
3. The equation involves a fraction, which suggests that we may need to eliminate the fraction to solve for n n .

STEP 2

1. Eliminate the fraction by multiplying both sides by the denominator.
2. Simplify the resulting equation.
3. Solve for n n .

STEP 3

To eliminate the fraction, multiply both sides of the equation by the denominator, which is 3:
35=35(4n1)3 3 \cdot 5 = 3 \cdot \frac{5(4n-1)}{3}
This simplifies to:
15=5(4n1) 15 = 5(4n-1)

STEP 4

Distribute the 5 on the right-hand side of the equation:
15=54n51 15 = 5 \cdot 4n - 5 \cdot 1
This simplifies to:
15=20n5 15 = 20n - 5

STEP 5

To solve for n n , first add 5 to both sides to isolate the term with n n :
15+5=20n5+5 15 + 5 = 20n - 5 + 5
This simplifies to:
20=20n 20 = 20n
Next, divide both sides by 20 to solve for n n :
2020=20n20 \frac{20}{20} = \frac{20n}{20}
This simplifies to:
1=n 1 = n
The solution is n=1 n = \boxed{1} .

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