Math / Numbers & Operations

Question44. What is the percent composition of bromine in the compound NaBr?

Studdy Solution

STEP 1

What is this asking? What percentage of the total weight of NaBr comes from the bromine atom? Watch out! Don't forget to look up the atomic masses of sodium (Na) and bromine (Br) on the periodic table!

STEP 2

1. Calculate the molar mass of NaBr.
2. Calculate the percent composition of bromine.

STEP 3

First, we find the atomic masses of sodium (Na) and bromine (Br) from the periodic table.
The atomic mass of Na is approximately $23$ amu (atomic mass units), and the atomic mass of Br is approximately $80$ amu.
Remember, these values can vary slightly depending on the periodic table you use, so always double-check!

STEP 4

Now, we add those masses together to get the molar mass of NaBr.
So, $23 + 80 = 103$ amu.
This means one mole of NaBr weighs $103$ grams.

STEP 5

To find the percent composition of bromine in NaBr, we'll divide the mass of bromine in one mole of NaBr by the total molar mass of NaBr.
This gives us the fraction: $\frac{80}{103}$ .
This fraction represents the portion of the total mass that comes from bromine.

STEP 6

Next, we multiply this fraction by $100\%$ to express it as a percentage: $\frac{80}{103} \cdot 100\%$ .

STEP 7

Calculating this gives us approximately $77.7\%$ .

STEP 8

The percent composition of bromine in NaBr is approximately $77.7\%$ .

Was this helpful?

Question44. What is the percent composition of bromine in the compound NaBr?

Studdy Solution

STEP 1

What is this asking? What percentage of the total weight of NaBr comes from the bromine atom? Watch out! Don't forget to look up the atomic masses of sodium (Na) and bromine (Br) on the periodic table!

STEP 2

1. Calculate the molar mass of NaBr.
2. Calculate the percent composition of bromine.

STEP 3

STEP 4

Now, we add those masses together to get the molar mass of NaBr.
So, $23 + 80 = 103$ amu.
This means one mole of NaBr weighs $103$ grams.

STEP 5

To find the percent composition of bromine in NaBr, we'll divide the mass of bromine in one mole of NaBr by the total molar mass of NaBr.
This gives us the fraction: $\frac{80}{103}$ .
This fraction represents the portion of the total mass that comes from bromine.

STEP 6

Next, we multiply this fraction by $100\%$ to express it as a percentage: $\frac{80}{103} \cdot 100\%$ .

STEP 7

Calculating this gives us approximately $77.7\%$ .

STEP 8

The percent composition of bromine in NaBr is approximately $77.7\%$ .

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Question44. What is the percent composition of bromine in the compound NaBr?

Studdy Solution

STEP 1

What is this asking? What percentage of the total weight of NaBr comes from the bromine atom? Watch out! Don't forget to look up the atomic masses of sodium (Na) and bromine (Br) on the periodic table!

STEP 2

1. Calculate the molar mass of NaBr.2. Calculate the percent composition of bromine.

STEP 3

STEP 4

Now, we **add** those masses together to get the molar mass of NaBr.So, 23+80=10323 + 80 = 10323+80=103 amu.This means one mole of NaBr weighs **103103103 grams**.

STEP 5

To find the percent composition of bromine in NaBr, we'll **divide** the mass of bromine in one mole of NaBr by the total molar mass of NaBr.This gives us the fraction: 80103 \frac{80}{103} 10380​.This fraction represents the portion of the total mass that comes from bromine.

STEP 6

Next, we **multiply** this fraction by 100%100\%100% to express it as a percentage: 80103⋅100% \frac{80}{103} \cdot 100\% 10380​⋅100%.

STEP 7

Calculating this gives us approximately 77.7%77.7\%77.7%.

STEP 8

The percent composition of bromine in NaBr is approximately **77.7%77.7\%77.7%**.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

1. Calculate the molar mass of NaBr.
2. Calculate the percent composition of bromine.

Now, we add those masses together to get the molar mass of NaBr.
So, $23 + 80 = 103$ amu.
This means one mole of NaBr weighs $103$ grams.

To find the percent composition of bromine in NaBr, we'll divide the mass of bromine in one mole of NaBr by the total molar mass of NaBr.
This gives us the fraction: $\frac{80}{103}$ .
This fraction represents the portion of the total mass that comes from bromine.

Next, we multiply this fraction by $100\%$ to express it as a percentage: $\frac{80}{103} \cdot 100\%$ .

Calculating this gives us approximately $77.7\%$ .

The percent composition of bromine in NaBr is approximately $77.7\%$ .