Math  /  Algebra

Question4(3x1)+4=364(3 x-1)+4=36 A. x=5x=5 B. x=2x=2 C. x=3x=3 D. x=3x=-3

Studdy Solution

STEP 1

What is this asking? We need to find the value of xx that makes the equation 4(3x1)+4=364(3x - 1) + 4 = 36 true. Watch out! Don't forget to apply the distributive property correctly and keep track of your positive and negative signs!

STEP 2

1. Simplify the equation
2. Isolate the term with xx
3. Solve for xx
4. Verify the solution

STEP 3

Let's **distribute** the 44 across the terms inside the parentheses.
Remember, this means multiplying 44 by both 3x3x and 1-1.
This gives us 43x41+4=364 \cdot 3x - 4 \cdot 1 + 4 = 36, which simplifies to 12x4+4=3612x - 4 + 4 = 36.

STEP 4

Now, we can **combine** the constant terms on the left side: 4+4=0-4 + 4 = 0.
So, our equation becomes 12x+0=3612x + 0 = 36, or simply 12x=3612x = 36.

STEP 5

To **isolate** xx, we need to divide both sides of the equation by the **coefficient** of xx, which is **12**.
Remember, we're dividing to one to isolate the xx.
So, we have 12x12=3612\frac{12x}{12} = \frac{36}{12}.

STEP 6

This simplifies to x=3x = 3.
So, our **potential solution** is x=3x = 3.

STEP 7

Let's **verify** this by substituting x=3x = 3 back into the original equation: 4(331)+4=4(91)+4=4(8)+4=32+4=364(3 \cdot 3 - 1) + 4 = 4(9 - 1) + 4 = 4(8) + 4 = 32 + 4 = 36.

STEP 8

Since both sides of the equation are equal, our solution x=3x = 3 is **correct**!

STEP 9

The correct answer is C, x=3x = 3.

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