QuestionFind the probability that a student in algebra does not take chemistry, given 40 in algebra, 10 in both, 50 in chemistry, and 100 not in either. Express as a fraction.

Studdy Solution

STEP 1

Assumptions1. The total number of students taking algebra is40. . The total number of students taking both algebra and chemistry is10.
3. The total number of students taking chemistry is50.
4. The total number of students not taking either algebra or chemistry is100.

STEP 2

First, we need to find the number of students taking algebra but not chemistry. We can do this by subtracting the number of students taking both algebra and chemistry from the total number of students taking algebra.
$Algebra\, but\, not\, chemistry = Total\, algebra - Both\, algebra\, and\, chemistry$

STEP 3

Now, plug in the given values for the total number of students taking algebra and the number of students taking both algebra and chemistry to calculate the number of students taking algebra but not chemistry.
$Algebra\, but\, not\, chemistry =40 -10$

STEP 4

Calculate the number of students taking algebra but not chemistry.
$Algebra\, but\, not\, chemistry =40 -10 =30$

STEP 5

Now that we have the number of students taking algebra but not chemistry, we can find the probability that a student taking algebra does not take chemistry. This can be found by dividing the number of students taking algebra but not chemistry by the total number of students taking algebra.
$Probability = Algebra\, but\, not\, chemistry / Total\, algebra$

STEP 6

Plug in the values for the number of students taking algebra but not chemistry and the total number of students taking algebra to calculate the probability.
$Probability =30 /40$

STEP 7

implify the fraction to get the probability.
$Probability =30 /40 =3 /4$ The probability that a student taking algebra does not take chemistry is3/4.

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QuestionFind the probability that a student in algebra does not take chemistry, given 40 in algebra, 10 in both, 50 in chemistry, and 100 not in either. Express as a fraction.

Studdy Solution

STEP 1

Assumptions1. The total number of students taking algebra is40. . The total number of students taking both algebra and chemistry is10.
3. The total number of students taking chemistry is50.
4. The total number of students not taking either algebra or chemistry is100.

STEP 2

STEP 3

Now, plug in the given values for the total number of students taking algebra and the number of students taking both algebra and chemistry to calculate the number of students taking algebra but not chemistry.
$Algebra\, but\, not\, chemistry =40 -10$

STEP 4

Calculate the number of students taking algebra but not chemistry.
$Algebra\, but\, not\, chemistry =40 -10 =30$

STEP 5

STEP 6

Plug in the values for the number of students taking algebra but not chemistry and the total number of students taking algebra to calculate the probability.
$Probability =30 /40$

STEP 7

implify the fraction to get the probability.
$Probability =30 /40 =3 /4$ The probability that a student taking algebra does not take chemistry is3/4.

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QuestionFind the probability that a student in algebra does not take chemistry, given 40 in algebra, 10 in both, 50 in chemistry, and 100 not in either. Express as a fraction.

Studdy Solution

STEP 1

Assumptions1. The total number of students taking algebra is40. . The total number of students taking both algebra and chemistry is10.3. The total number of students taking chemistry is50.4. The total number of students not taking either algebra or chemistry is100.

STEP 2

STEP 3

STEP 4

Calculate the number of students taking algebra but not chemistry.Algebra but not chemistry=40−10=30Algebra\, but\, not\, chemistry =40 -10 =30Algebrabutnotchemistry=40−10=30

STEP 5

STEP 6

Plug in the values for the number of students taking algebra but not chemistry and the total number of students taking algebra to calculate the probability.Probability=30/40Probability =30 /40Probability=30/40

STEP 7

implify the fraction to get the probability.Probability=30/40=3/4Probability =30 /40 =3 /4Probability=30/40=3/4The probability that a student taking algebra does not take chemistry is3/4.

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Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Assumptions1. The total number of students taking algebra is40. . The total number of students taking both algebra and chemistry is10.
3. The total number of students taking chemistry is50.
4. The total number of students not taking either algebra or chemistry is100.

Calculate the number of students taking algebra but not chemistry.
$Algebra\, but\, not\, chemistry =40 -10 =30$

Plug in the values for the number of students taking algebra but not chemistry and the total number of students taking algebra to calculate the probability.
$Probability =30 /40$

implify the fraction to get the probability.
$Probability =30 /40 =3 /4$ The probability that a student taking algebra does not take chemistry is3/4.