QuestionCalculate $32 \times 61$ and add $192$ to get the final result. What is the answer?

Studdy Solution

STEP 1

Assumptions1. We are performing a multiplication operation between two numbers,32 and61. . We are using the long multiplication method, where each digit of the second number is multiplied by each digit of the first number, starting from the rightmost digit.
3. The results of these multiplications are then added together to get the final result.

STEP 2

First, we multiply the rightmost digit of the second number (1) by each digit of the first number (32), starting from the rightmost digit.
$1 \\times2 =2$ $1 \\times =$

STEP 3

We then write these results below the line, starting from the rightmost column. The result of multiplying by the tens digit (3) is written in the tens column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\ \hline\end{array}$

STEP 4

Next, we multiply the leftmost digit of the second number (6) by each digit of the first number (32), starting from the rightmost digit. $6 \\times2 =12$ $6 \\times3 =18$

STEP 5

We then write these results below the line, starting from the tens column. The result of multiplying by the hundreds digit (18) is written in the hundreds column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\12 \\18 \\ \hline\end{array}$

STEP 6

Finally, we add the results together to get the final result.
$2 +300 +1200 +1800 =1952$ The result of the multiplication operation is1952.

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QuestionCalculate $32 \times 61$ and add $192$ to get the final result. What is the answer?

Studdy Solution

STEP 1

STEP 2

First, we multiply the rightmost digit of the second number (1) by each digit of the first number (32), starting from the rightmost digit.
$1 \\times2 =2$ $1 \\times =$

STEP 3

We then write these results below the line, starting from the rightmost column. The result of multiplying by the tens digit (3) is written in the tens column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\ \hline\end{array}$

STEP 4

Next, we multiply the leftmost digit of the second number (6) by each digit of the first number (32), starting from the rightmost digit. $6 \\times2 =12$ $6 \\times3 =18$

STEP 5

We then write these results below the line, starting from the tens column. The result of multiplying by the hundreds digit (18) is written in the hundreds column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\12 \\18 \\ \hline\end{array}$

STEP 6

Finally, we add the results together to get the final result.
$2 +300 +1200 +1800 =1952$ The result of the multiplication operation is1952.

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QuestionCalculate 32×6132 \times 6132×61 and add 192192192 to get the final result. What is the answer?

Studdy Solution

STEP 1

STEP 2

First, we multiply the rightmost digit of the second number (1) by each digit of the first number (32), starting from the rightmost digit.1times2=21 \\times2 =21times2=21times=1 \\times =1times=

STEP 3

We then write these results below the line, starting from the rightmost column. The result of multiplying by the tens digit (3) is written in the tens column.32×6123\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\ \hline\end{array}32×6123​​

STEP 4

Next, we multiply the leftmost digit of the second number (6) by each digit of the first number (32), starting from the rightmost digit.6times2=126 \\times2 =126times2=126times3=186 \\times3 =186times3=18

STEP 5

We then write these results below the line, starting from the tens column. The result of multiplying by the hundreds digit (18) is written in the hundreds column.32×61231218\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\12 \\18 \\ \hline\end{array}32×61231218​​

STEP 6

Finally, we add the results together to get the final result.2+300+1200+1800=19522 +300 +1200 +1800 =19522+300+1200+1800=1952The result of the multiplication operation is1952.

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QuestionCalculate $32 \times 61$ and add $192$ to get the final result. What is the answer?

First, we multiply the rightmost digit of the second number (1) by each digit of the first number (32), starting from the rightmost digit.
$1 \\times2 =2$ $1 \\times =$

We then write these results below the line, starting from the rightmost column. The result of multiplying by the tens digit (3) is written in the tens column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\ \hline\end{array}$

Next, we multiply the leftmost digit of the second number (6) by each digit of the first number (32), starting from the rightmost digit. $6 \\times2 =12$ $6 \\times3 =18$

We then write these results below the line, starting from the tens column. The result of multiplying by the hundreds digit (18) is written in the hundreds column.
$\begin{array}{r}32 \\ \times61 \\ \hline2 \\3 \\12 \\18 \\ \hline\end{array}$

Finally, we add the results together to get the final result.
$2 +300 +1200 +1800 =1952$ The result of the multiplication operation is1952.