Math  /  Algebra

Question3y28y+4=5y3 y^{2}-8 y+4=5 y

Studdy Solution

STEP 1

What is this asking? We're trying to find the mystery value(s) of yy that make this equation true! Watch out! Don't forget to set the equation equal to zero *before* factoring.
Also, remember there might be more than one solution for yy!

STEP 2

1. Set to Zero
2. Factor the Quadratic
3. Solve for *y*

STEP 3

Alright, let's **kick things off** by rearranging our equation to get a nice, clean zero on one side.
We can do this by subtracting 5y5y from both sides of the equation.
Remember, what we do to one side, we *must* do to the other to keep things balanced!
3y28y+45y=5y5y 3y^2 - 8y + 4 - 5y = 5y - 5y 3y213y+4=0 3y^2 - 13y + 4 = 0

STEP 4

Boom! Now we have a **quadratic equation** in the beautiful **standard form**: ax2+bx+c=0ax^2 + bx + c = 0.
In our case, aa is **3**, bb is **-13**, and cc is **4**.
This setup is *perfect* for factoring!

STEP 5

Time to **factor**!
We're looking for two numbers that multiply to ac=34=12a \cdot c = 3 \cdot 4 = 12 and add up to b=13b = -13.
Let's see... 1-1 and 12-12 fit the bill perfectly!

STEP 6

Now, let's **rewrite** our equation using these magical numbers:
3y212yy+4=0 3y^2 - 12y - y + 4 = 0

STEP 7

Let's **group** the terms and **factor** out the greatest common factor from each group:
3y(y4)1(y4)=0 3y(y - 4) - 1(y - 4) = 0

STEP 8

Notice that (y4)(y-4) is a **common factor**.
Let's factor that out too!
(3y1)(y4)=0 (3y - 1)(y - 4) = 0

STEP 9

Now, we have two factors multiplied together equaling zero.
This means either 3y1=03y - 1 = 0 or y4=0y - 4 = 0.
This is our chance to shine!

STEP 10

Let's solve 3y1=03y - 1 = 0. **Add** 1 to both sides:
3y1+1=0+1 3y - 1 + 1 = 0 + 1 3y=1 3y = 1 Now, **divide** both sides by 3:
3y3=13 \frac{3y}{3} = \frac{1}{3} y=13 y = \frac{1}{3}

STEP 11

Next, let's solve y4=0y - 4 = 0. **Add** 4 to both sides:
y4+4=0+4 y - 4 + 4 = 0 + 4 y=4 y = 4

STEP 12

So, the **solutions** to our original equation are y=13y = \frac{1}{3} and y=4y = 4!
We found *two* answers!
Double the fun!

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