QuestionSolve for $x$ in the equation: $3x + 2 = 2(x + 1) + x$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x + =(x +1) + x$ . The variable x is a real number

STEP 2

First, we need to simplify the equation. We can do this by distributing the2 in the expression $2(x +1)$ .
$x +2 =2x +2 + x$

STEP 3

Now, combine like terms on both sides of the equation.
$3x +2 =3x +2$

STEP 4

Subtract $3x$ from both sides of the equation to isolate $x$ .
$3x -3x +2 =3x -3x +2$

STEP 5

implify the equation.
$2 =2$

STEP 6

The equation $2 =2$ is always true, so the original equation $3x +2 =2(x +1) + x$ has infinitely many solutions. Any real number can be a solution for $x$ .

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QuestionSolve for $x$ in the equation: $3x + 2 = 2(x + 1) + x$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $3x + =(x +1) + x$ . The variable x is a real number

STEP 2

First, we need to simplify the equation. We can do this by distributing the2 in the expression $2(x +1)$ .
$x +2 =2x +2 + x$

STEP 3

Now, combine like terms on both sides of the equation.
$3x +2 =3x +2$

STEP 4

Subtract $3x$ from both sides of the equation to isolate $x$ .
$3x -3x +2 =3x -3x +2$

STEP 5

implify the equation.
$2 =2$

STEP 6

The equation $2 =2$ is always true, so the original equation $3x +2 =2(x +1) + x$ has infinitely many solutions. Any real number can be a solution for $x$ .

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QuestionSolve for xxx in the equation: 3x+2=2(x+1)+x3x + 2 = 2(x + 1) + x3x+2=2(x+1)+x.

Studdy Solution

STEP 1

Assumptions1. The equation is 3x+=(x+1)+x3x + =(x +1) + x3x+=(x+1)+x . The variable x is a real number

STEP 2

First, we need to simplify the equation. We can do this by distributing the2 in the expression 2(x+1)2(x +1)2(x+1).x+2=2x+2+xx +2 =2x +2 + xx+2=2x+2+x

STEP 3

Now, combine like terms on both sides of the equation.3x+2=3x+23x +2 =3x +23x+2=3x+2

STEP 4

Subtract 3x3x3x from both sides of the equation to isolate xxx.3x−3x+2=3x−3x+23x -3x +2 =3x -3x +23x−3x+2=3x−3x+2

STEP 5

implify the equation.2=22 =22=2

STEP 6

The equation 2=22 =22=2 is always true, so the original equation 3x+2=2(x+1)+x3x +2 =2(x +1) + x3x+2=2(x+1)+x has infinitely many solutions. Any real number can be a solution for xxx.

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QuestionSolve for $x$ in the equation: $3x + 2 = 2(x + 1) + x$ .

Assumptions1. The equation is $3x + =(x +1) + x$ . The variable x is a real number

First, we need to simplify the equation. We can do this by distributing the2 in the expression $2(x +1)$ .
$x +2 =2x +2 + x$

Now, combine like terms on both sides of the equation.
$3x +2 =3x +2$

Subtract $3x$ from both sides of the equation to isolate $x$ .
$3x -3x +2 =3x -3x +2$

implify the equation.
$2 =2$

The equation $2 =2$ is always true, so the original equation $3x +2 =2(x +1) + x$ has infinitely many solutions. Any real number can be a solution for $x$ .