Math / Algebra

Question $2(y+5)-2(y-1)$

Studdy Solution

STEP 1

1. The expression involves basic algebraic operations.
2. We can simplify the expression by distributing and combining like terms.

STEP 2

1. Distribute the constants across the terms inside the parentheses.
2. Combine like terms to simplify the expression.

STEP 3

Distribute the constant $2$ across the terms inside the first set of parentheses:
$2(y + 5) = 2y + 10$

STEP 4

Distribute the constant $-2$ across the terms inside the second set of parentheses:
$-2(y - 1) = -2y + 2$

STEP 5

Combine the results from the distribution steps:
$2y + 10 - 2y + 2$

STEP 6

Combine like terms. The $2y$ and $-2y$ cancel each other out:
$2y - 2y + 10 + 2 = 0 + 12$

STEP 7

The simplified expression is:
$12$

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Question $2(y+5)-2(y-1)$

Studdy Solution

STEP 1

1. The expression involves basic algebraic operations.
2. We can simplify the expression by distributing and combining like terms.

STEP 2

1. Distribute the constants across the terms inside the parentheses.
2. Combine like terms to simplify the expression.

STEP 3

Distribute the constant $2$ across the terms inside the first set of parentheses:
$2(y + 5) = 2y + 10$

STEP 4

Distribute the constant $-2$ across the terms inside the second set of parentheses:
$-2(y - 1) = -2y + 2$

STEP 5

Combine the results from the distribution steps:
$2y + 10 - 2y + 2$

STEP 6

Combine like terms. The $2y$ and $-2y$ cancel each other out:
$2y - 2y + 10 + 2 = 0 + 12$

STEP 7

The simplified expression is:
$12$

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Question2(y+5)−2(y−1)2(y+5)-2(y-1)2(y+5)−2(y−1)

Studdy Solution

STEP 1

1. The expression involves basic algebraic operations.2. We can simplify the expression by distributing and combining like terms.

STEP 2

1. Distribute the constants across the terms inside the parentheses.2. Combine like terms to simplify the expression.

STEP 3

Distribute the constant 222 across the terms inside the first set of parentheses:2(y+5)=2y+10 2(y + 5) = 2y + 10 2(y+5)=2y+10

STEP 4

Distribute the constant −2-2−2 across the terms inside the second set of parentheses:−2(y−1)=−2y+2 -2(y - 1) = -2y + 2 −2(y−1)=−2y+2

STEP 5

Combine the results from the distribution steps:2y+10−2y+2 2y + 10 - 2y + 2 2y+10−2y+2

STEP 6

Combine like terms. The 2y2y2y and −2y-2y−2y cancel each other out:2y−2y+10+2=0+12 2y - 2y + 10 + 2 = 0 + 12 2y−2y+10+2=0+12

STEP 7

The simplified expression is:12 12 12

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Question $2(y+5)-2(y-1)$

1. The expression involves basic algebraic operations.
2. We can simplify the expression by distributing and combining like terms.

1. Distribute the constants across the terms inside the parentheses.
2. Combine like terms to simplify the expression.

Distribute the constant $2$ across the terms inside the first set of parentheses:
$2(y + 5) = 2y + 10$

Distribute the constant $-2$ across the terms inside the second set of parentheses:
$-2(y - 1) = -2y + 2$

Combine the results from the distribution steps:
$2y + 10 - 2y + 2$

Combine like terms. The $2y$ and $-2y$ cancel each other out:
$2y - 2y + 10 + 2 = 0 + 12$

The simplified expression is:
$12$