Math  /  Numbers & Operations

Question2,784
2. Estimate: \qquad 3. Estimate: \qquad \qquad 673×48×38\begin{array}{r} 673 \\ \times \quad 48 \\ \times \quad 38 \\ \hline \end{array}
4. Estimate: \qquad

Studdy Solution

STEP 1

1. We are tasked with estimating the products of three multiplication problems.
2. Estimation involves rounding numbers to the nearest ten or hundred to simplify calculations.
3. The problems to estimate are: - 673×28673 \times 28 - 48×3848 \times 38 - 359×52359 \times 52

STEP 2

1. Estimate 673×28673 \times 28
2. Estimate 48×3848 \times 38
3. Estimate 359×52359 \times 52

STEP 3

Round each number in the multiplication problem 673×28673 \times 28 to the nearest ten.
- 673673 rounds to 670670 - 2828 rounds to 3030

STEP 4

Calculate the estimated product of the rounded numbers.
670×30=670×(3×10)=(670×3)×10=2010×10=20100 670 \times 30 = 670 \times (3 \times 10) = (670 \times 3) \times 10 = 2010 \times 10 = 20100

STEP 5

Round each number in the multiplication problem 48×3848 \times 38 to the nearest ten.
- 4848 rounds to 5050 - 3838 rounds to 4040

STEP 6

Calculate the estimated product of the rounded numbers.
50×40=(5×10)×(4×10)=5×4×100=20×100=2000 50 \times 40 = (5 \times 10) \times (4 \times 10) = 5 \times 4 \times 100 = 20 \times 100 = 2000

STEP 7

Round each number in the multiplication problem 359×52359 \times 52 to the nearest ten.
- 359359 rounds to 360360 - 5252 rounds to 5050

STEP 8

Calculate the estimated product of the rounded numbers.
360×50=(36×10)×(5×10)=36×5×100=180×100=18000 360 \times 50 = (36 \times 10) \times (5 \times 10) = 36 \times 5 \times 100 = 180 \times 100 = 18000
The estimated products are:
1. 673×2820100673 \times 28 \approx 20100
2. 48×38200048 \times 38 \approx 2000
3. 359×5218000359 \times 52 \approx 18000

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