Math  /  Algebra

Question26 Een onbekende verbinding heeft een molaire massa van90,1 g mol1\operatorname{van} 90,1 \mathrm{~g} \mathrm{~mol}^{-1}. De samenstelling van deze verbinding wordt in een laboratorium bepaald. De stof blijkt voor 40,0 massa\% uit koolstof te bestaan, voor 6,7 massa\% uit waterstof en voor 53,3 massa\% uit zuurstof. a Bereken hoeveel gram koolstof, waterstof en zuurstof in een mol van de onbekende stof zit.

Studdy Solution

STEP 1

1. The unknown compound has a molar mass of 90.1g/mol 90.1 \, \mathrm{g/mol} .
2. The compound consists of 40.0% carbon by mass, 6.7% hydrogen by mass, and 53.3% oxygen by mass.
3. We need to calculate the mass of carbon, hydrogen, and oxygen in one mole of the compound.

STEP 2

1. Calculate the mass of carbon in one mole of the compound.
2. Calculate the mass of hydrogen in one mole of the compound.
3. Calculate the mass of oxygen in one mole of the compound.

STEP 3

Calculate the mass of carbon in one mole of the compound.
Given that carbon makes up 40.0% of the compound by mass, we can find the mass of carbon in one mole by using the formula:
Mass of carbon=(40.0100)×90.1g/mol \text{Mass of carbon} = \left(\frac{40.0}{100}\right) \times 90.1 \, \mathrm{g/mol}
Mass of carbon=0.40×90.1g/mol \text{Mass of carbon} = 0.40 \times 90.1 \, \mathrm{g/mol}
Mass of carbon=36.04g \text{Mass of carbon} = 36.04 \, \mathrm{g}

STEP 4

Calculate the mass of hydrogen in one mole of the compound.
Given that hydrogen makes up 6.7% of the compound by mass, we can find the mass of hydrogen in one mole by using the formula:
Mass of hydrogen=(6.7100)×90.1g/mol \text{Mass of hydrogen} = \left(\frac{6.7}{100}\right) \times 90.1 \, \mathrm{g/mol}
Mass of hydrogen=0.067×90.1g/mol \text{Mass of hydrogen} = 0.067 \times 90.1 \, \mathrm{g/mol}
Mass of hydrogen=6.0367g \text{Mass of hydrogen} = 6.0367 \, \mathrm{g}

STEP 5

Calculate the mass of oxygen in one mole of the compound.
Given that oxygen makes up 53.3% of the compound by mass, we can find the mass of oxygen in one mole by using the formula:
Mass of oxygen=(53.3100)×90.1g/mol \text{Mass of oxygen} = \left(\frac{53.3}{100}\right) \times 90.1 \, \mathrm{g/mol}
Mass of oxygen=0.533×90.1g/mol \text{Mass of oxygen} = 0.533 \times 90.1 \, \mathrm{g/mol}
Mass of oxygen=48.0663g \text{Mass of oxygen} = 48.0663 \, \mathrm{g}
The masses of carbon, hydrogen, and oxygen in one mole of the compound are:
- Carbon: 36.04g 36.04 \, \mathrm{g} - Hydrogen: 6.0367g 6.0367 \, \mathrm{g} - Oxygen: 48.0663g 48.0663 \, \mathrm{g}

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