QuestionSolve for $c$ in the equation: $-20c - 2c - 6 = 16$ . What is $c$ ?

Studdy Solution

STEP 1

Assumptions1. The equation given is $-20c -c -6 =16$ . We are solving for $c$

STEP 2

First, we need to combine like terms on the left side of the equation.
$-20c -2c -6 =16$ becomes $-22c -6 =16$

STEP 3

Next, we need to isolate the term with $c$ on one side of the equation. We can do this by adding $6$ to both sides of the equation.
$-22c -6 +6 =16 +6$

STEP 4

implify the equation.
$-22c =22$

STEP 5

Finally, to solve for $c$ , we need to divide both sides of the equation by $-22$ .
$c = \frac{22}{-22}$

STEP 6

implify the right side of the equation to find the value of $c$ .
$c = -1$ So, $c = -1$ .

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QuestionSolve for $c$ in the equation: $-20c - 2c - 6 = 16$ . What is $c$ ?

Studdy Solution

STEP 1

Assumptions1. The equation given is $-20c -c -6 =16$ . We are solving for $c$

STEP 2

First, we need to combine like terms on the left side of the equation.
$-20c -2c -6 =16$ becomes $-22c -6 =16$

STEP 3

Next, we need to isolate the term with $c$ on one side of the equation. We can do this by adding $6$ to both sides of the equation.
$-22c -6 +6 =16 +6$

STEP 4

implify the equation.
$-22c =22$

STEP 5

Finally, to solve for $c$ , we need to divide both sides of the equation by $-22$ .
$c = \frac{22}{-22}$

STEP 6

implify the right side of the equation to find the value of $c$ .
$c = -1$ So, $c = -1$ .

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QuestionSolve for ccc in the equation: −20c−2c−6=16-20c - 2c - 6 = 16−20c−2c−6=16. What is ccc?

Studdy Solution

STEP 1

Assumptions1. The equation given is −20c−c−6=16-20c -c -6 =16−20c−c−6=16 . We are solving for ccc

STEP 2

First, we need to combine like terms on the left side of the equation.−20c−2c−6=16-20c -2c -6 =16−20c−2c−6=16becomes−22c−6=16-22c -6 =16−22c−6=16

STEP 3

Next, we need to isolate the term with ccc on one side of the equation. We can do this by adding 666 to both sides of the equation.−22c−6+6=16+6-22c -6 +6 =16 +6−22c−6+6=16+6

STEP 4

implify the equation.−22c=22-22c =22−22c=22

STEP 5

Finally, to solve for ccc, we need to divide both sides of the equation by −22-22−22.c=22−22c = \frac{22}{-22}c=−2222​

STEP 6

implify the right side of the equation to find the value of ccc.c=−1c = -1c=−1So, c=−1c = -1c=−1.

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QuestionSolve for $c$ in the equation: $-20c - 2c - 6 = 16$ . What is $c$ ?

Assumptions1. The equation given is $-20c -c -6 =16$ . We are solving for $c$

First, we need to combine like terms on the left side of the equation.
$-20c -2c -6 =16$ becomes $-22c -6 =16$

Next, we need to isolate the term with $c$ on one side of the equation. We can do this by adding $6$ to both sides of the equation.
$-22c -6 +6 =16 +6$

implify the equation.
$-22c =22$

Finally, to solve for $c$ , we need to divide both sides of the equation by $-22$ .
$c = \frac{22}{-22}$

implify the right side of the equation to find the value of $c$ .
$c = -1$ So, $c = -1$ .