Math / Algebra

Question2. $y=x-13$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline 3 & & & \\ \hline 6 & & & \\ \hline 9 & & & \\ \hline 12 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to plug some $x$ values into the equation $y = x - 13$ and find the matching $y$ values, then write them as coordinate pairs! Watch out! Make sure to subtract correctly, even with negative numbers!

STEP 2

1. Calculate $y$ when $x = 3$ .
2. Calculate $y$ when $x = 6$ .
3. Calculate $y$ when $x = 9$ .
4. Calculate $y$ when $x = 12$ .

STEP 3

Alright, let's kick things off with $x = 3$ !
We've got our super cool equation $y = x - 13$ .
Let's plug in our shiny new $x$ value: $y = 3 - 13$ .

STEP 4

Time for some subtraction action: $3 - 13 = -10$ .
So, when $x = 3$ , our amazing $y$ is $-10$ !
This gives us the coordinate pair $(3, -10)$ .
Woohoo!

STEP 5

Next up, $x = 6$ !
Back to our trusty equation: $y = x - 13$ . Substitute $x = 6$ to get $y = 6 - 13$ .

STEP 6

Subtract and we find $y = -7$ .
So, the coordinate pair is $(6, -7)$ !
We're on a roll!

STEP 7

Now for $x = 9$ !
Our equation $y = x - 13$ is still here for us. Plugging in $x = 9$ gives us $y = 9 - 13$ .

STEP 8

Subtracting gives us $y = -4$ .
This means our coordinate pair is $(9, -4)$ !
Getting close to positive $y$ values, I can feel it.

STEP 9

Last one, $x = 12$ !
Using our equation $y = x - 13$ one last time, we substitute $x = 12$ to get $y = 12 - 13$ .

STEP 10

A final subtraction gives us $y = -1$ .
Our final coordinate pair is $(12, -1)$ !
We did it!

STEP 11

When $x = 3$ , $y = -10$ , giving us the point $(3, -10)$ . When $x = 6$ , $y = -7$ , giving us the point $(6, -7)$ . When $x = 9$ , $y = -4$ , giving us the point $(9, -4)$ . When $x = 12$ , $y = -1$ , giving us the point $(12, -1)$ .

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Question2. $y=x-13$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline 3 & & & \\ \hline 6 & & & \\ \hline 9 & & & \\ \hline 12 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to plug some $x$ values into the equation $y = x - 13$ and find the matching $y$ values, then write them as coordinate pairs! Watch out! Make sure to subtract correctly, even with negative numbers!

STEP 2

1. Calculate $y$ when $x = 3$ .
2. Calculate $y$ when $x = 6$ .
3. Calculate $y$ when $x = 9$ .
4. Calculate $y$ when $x = 12$ .

STEP 3

Alright, let's kick things off with $x = 3$ !
We've got our super cool equation $y = x - 13$ .
Let's plug in our shiny new $x$ value: $y = 3 - 13$ .

STEP 4

Time for some subtraction action: $3 - 13 = -10$ .
So, when $x = 3$ , our amazing $y$ is $-10$ !
This gives us the coordinate pair $(3, -10)$ .
Woohoo!

STEP 5

Next up, $x = 6$ !
Back to our trusty equation: $y = x - 13$ . Substitute $x = 6$ to get $y = 6 - 13$ .

STEP 6

Subtract and we find $y = -7$ .
So, the coordinate pair is $(6, -7)$ !
We're on a roll!

STEP 7

Now for $x = 9$ !
Our equation $y = x - 13$ is still here for us. Plugging in $x = 9$ gives us $y = 9 - 13$ .

STEP 8

Subtracting gives us $y = -4$ .
This means our coordinate pair is $(9, -4)$ !
Getting close to positive $y$ values, I can feel it.

STEP 9

Last one, $x = 12$ !
Using our equation $y = x - 13$ one last time, we substitute $x = 12$ to get $y = 12 - 13$ .

STEP 10

A final subtraction gives us $y = -1$ .
Our final coordinate pair is $(12, -1)$ !
We did it!

STEP 11

When $x = 3$ , $y = -10$ , giving us the point $(3, -10)$ . When $x = 6$ , $y = -7$ , giving us the point $(6, -7)$ . When $x = 9$ , $y = -4$ , giving us the point $(9, -4)$ . When $x = 12$ , $y = -1$ , giving us the point $(12, -1)$ .

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Question2. y=x−13y=x-13y=x−13 \begin{tabular}{|c|l|c|c|} \hlinexxx & & yyy & (x,y)(x, y)(x,y) \\ \hline 3 & & & \\ \hline 6 & & & \\ \hline 9 & & & \\ \hline 12 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to plug some xxx values into the equation y=x−13y = x - 13y=x−13 and find the matching yyy values, then write them as coordinate pairs! Watch out! Make sure to subtract correctly, even with negative numbers!

STEP 2

1. Calculate yyy when x=3x = 3x=3.2. Calculate yyy when x=6x = 6x=6.3. Calculate yyy when x=9x = 9x=9.4. Calculate yyy when x=12x = 12x=12.

STEP 3

Alright, let's **kick things off** with x=3x = 3x=3!We've got our **super cool** equation y=x−13y = x - 13y=x−13.Let's **plug in** our **shiny** new xxx value: y=3−13y = 3 - 13y=3−13.

STEP 4

Time for some **subtraction action**: 3−13=−103 - 13 = -103−13=−10.So, when x=3x = 3x=3, our **amazing** yyy is −10-10−10!This gives us the **coordinate pair** (3,−10)(3, -10)(3,−10).Woohoo!

STEP 5

Next up, x=6x = 6x=6!Back to our **trusty** equation: y=x−13y = x - 13y=x−13. **Substitute** x=6x = 6x=6 to get y=6−13y = 6 - 13y=6−13.

STEP 6

**Subtract** and we find y=−7y = -7y=−7.So, the **coordinate pair** is (6,−7)(6, -7)(6,−7)!We're on a roll!

STEP 7

Now for x=9x = 9x=9!Our equation y=x−13y = x - 13y=x−13 is still here for us. **Plugging in** x=9x = 9x=9 gives us y=9−13y = 9 - 13y=9−13.

STEP 8

**Subtracting** gives us y=−4y = -4y=−4.This means our **coordinate pair** is (9,−4)(9, -4)(9,−4)!Getting close to positive yyy values, I can feel it.

STEP 9

Last one, x=12x = 12x=12!Using our equation y=x−13y = x - 13y=x−13 one last time, we **substitute** x=12x = 12x=12 to get y=12−13y = 12 - 13y=12−13.

STEP 10

A final **subtraction** gives us y=−1y = -1y=−1.Our final **coordinate pair** is (12,−1)(12, -1)(12,−1)!We did it!

STEP 11

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Question2. $y=x-13$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline 3 & & & \\ \hline 6 & & & \\ \hline 9 & & & \\ \hline 12 & & & \\ \hline \end{tabular}

What is this asking? We need to plug some $x$ values into the equation $y = x - 13$ and find the matching $y$ values, then write them as coordinate pairs! Watch out! Make sure to subtract correctly, even with negative numbers!

1. Calculate $y$ when $x = 3$ .
2. Calculate $y$ when $x = 6$ .
3. Calculate $y$ when $x = 9$ .
4. Calculate $y$ when $x = 12$ .

Alright, let's kick things off with $x = 3$ !
We've got our super cool equation $y = x - 13$ .
Let's plug in our shiny new $x$ value: $y = 3 - 13$ .

Time for some subtraction action: $3 - 13 = -10$ .
So, when $x = 3$ , our amazing $y$ is $-10$ !
This gives us the coordinate pair $(3, -10)$ .
Woohoo!

Next up, $x = 6$ !
Back to our trusty equation: $y = x - 13$ . Substitute $x = 6$ to get $y = 6 - 13$ .

Subtract and we find $y = -7$ .
So, the coordinate pair is $(6, -7)$ !
We're on a roll!

Now for $x = 9$ !
Our equation $y = x - 13$ is still here for us. Plugging in $x = 9$ gives us $y = 9 - 13$ .

Subtracting gives us $y = -4$ .
This means our coordinate pair is $(9, -4)$ !
Getting close to positive $y$ values, I can feel it.

Last one, $x = 12$ !
Using our equation $y = x - 13$ one last time, we substitute $x = 12$ to get $y = 12 - 13$ .

A final subtraction gives us $y = -1$ .
Our final coordinate pair is $(12, -1)$ !
We did it!