Math

QuestionSolve for xx: 23x4+15=432|3 x-4|+15=43

Studdy Solution

STEP 1

Assumptions1. The absolute value of a number is its distance from zero on the number line, and is always positive or zero. . The equation given is 3x4+15=43|3x-4|+15=43.

STEP 2

First, we isolate the absolute value term by subtracting15 from both sides of the equation.
2x4+1515=43152|x-4|+15-15=43-15

STEP 3

implify the equation.
23x=282|3x-|=28

STEP 4

Next, we divide both sides of the equation by2 to isolate the absolute value term.
23x42=282\frac{2|3x-4|}{2}=\frac{28}{2}

STEP 5

implify the equation.
3x4=14|3x-4|=14

STEP 6

Now, we can remove the absolute value by setting up two equations, one for the positive value and one for the negative value.
3x4=14and3x4=143x-4=14 \quad and \quad3x-4=-14

STEP 7

olve the first equation by adding4 to both sides.
3x4+4=14+43x-4+4=14+4

STEP 8

implify the equation.
3x=183x=18

STEP 9

Divide both sides by3 to solve for x.
3x3=183\frac{3x}{3}=\frac{18}{3}

STEP 10

implify the equation.
x=6x=6

STEP 11

Now, solve the second equation by adding4 to both sides.
3x4+4=14+43x-4+4=-14+4

STEP 12

implify the equation.
x=10x=-10

STEP 13

Divide both sides by3 to solve for x.
3x3=103\frac{3x}{3}=\frac{-10}{3}

STEP 14

implify the equation.
x=103x=-\frac{10}{3}The solutions to the equation are x=6x=6 and x=103x=-\frac{10}{3}.

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