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Math

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PROBLEM

2. Sketch the following graphs on separate diagrams.
(a) y=(x+a)3,a>0y=(x+a)^{3}, a>0
(b) y=x3b,b>0y=x^{3}-b, b>0

STEP 1

1. We are dealing with cubic functions, which have the general form y=x3 y = x^3 .
2. The transformations involve horizontal and vertical shifts.
3. The parameter a a in part (a) represents a horizontal shift.
4. The parameter b b in part (b) represents a vertical shift.

STEP 2

1. Analyze and sketch the graph for y=(x+a)3 y = (x+a)^3 .
2. Analyze and sketch the graph for y=x3b y = x^3 - b .

STEP 3

The base function is y=x3 y = x^3 , which is a cubic function with an inflection point at the origin (0,0).

STEP 4

For y=(x+a)3 y = (x+a)^3 , the graph of y=x3 y = x^3 is shifted horizontally to the left by a a units because a>0 a > 0 .

STEP 5

Sketch the graph of y=(x+a)3 y = (x+a)^3 :
- Start with the graph of y=x3 y = x^3 .
- Shift every point on this graph a a units to the left.
- The inflection point moves from (0,0) to (-a,0).

STEP 6

The base function is again y=x3 y = x^3 .

STEP 7

For y=x3b y = x^3 - b , the graph of y=x3 y = x^3 is shifted vertically downward by b b units because b>0 b > 0 .

SOLUTION

Sketch the graph of y=x3b y = x^3 - b :
- Start with the graph of y=x3 y = x^3 .
- Shift every point on this graph b b units downward.
- The inflection point moves from (0,0) to (0,-b).
The graphs for each function have been sketched with the described transformations.

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