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Math  /  Algebra

Question(2) c+12=48c+\frac{1}{2}=\frac{4}{8}

Studdy Solution

STEP 1

What is this asking? We need to find the value of cc that makes this equation true! Watch out! Don't be tricked by the fractions; we'll handle them with care.

STEP 2

1. Simplify the equation
2. Isolate cc
3. Calculate cc

STEP 3

We have the fraction 48\frac{4}{8}.
Both the **numerator** and the **denominator** are divisible by **4**.
Dividing both by **4**, we get 48=4÷48÷4=12\frac{4}{8} = \frac{4 \div 4}{8 \div 4} = \frac{1}{2}.
So, our equation becomes c+12=12c + \frac{1}{2} = \frac{1}{2}.
This makes things much simpler!

STEP 4

To get cc by itself, we need to subtract 12\frac{1}{2} from both sides of the equation.
Remember, what we do to one side, we *must* do to the other to keep the equation balanced!
This gives us: c+12−12=12−12c + \frac{1}{2} - \frac{1}{2} = \frac{1}{2} - \frac{1}{2}.

STEP 5

On the left side, 12−12\frac{1}{2} - \frac{1}{2} adds to **zero**, leaving just cc.
On the right side, 12−12\frac{1}{2} - \frac{1}{2} also adds to **zero**.
So, we have c+0=0c + 0 = 0, which simplifies to c=0c = 0.

STEP 6

From the previous step, we found that c=0c = 0.
That's it!

STEP 7

The value of cc that satisfies the equation is c=0c = 0.

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