QuestionCalculate $\frac{(2.40 \frac{\mathrm{g}}{\mathrm{mL}})(\frac{1 \mathrm{~mL}}{10^{-3} \mathrm{~L}})}{(116.86 \frac{\mathrm{g}}{\mathrm{mol}})}$ .

Studdy Solution

STEP 1

Assumptions1. The density of the substance is $.40 \frac{\mathrm{g}}{\mathrm{m}}$ . The conversion factor from mL to L is $\frac{1 \mathrm{~m}}{10^{-3} \mathrm{~}}$
3. The molar mass of the substance is $116.86 \frac{\mathrm{g}}{\mathrm{mol}}$

STEP 2

We need to calculate the given expression which is a division of two fractions. We can simplify this by multiplying the first fraction by the reciprocal of the second fraction.
$\frac{\left(2.40 \frac{\mathrm{g}}{\mathrm{m}}\right)\left(\frac{1 \mathrm{~m}}{10^{-} \mathrm{~}}\right)}{\left(116.86 \frac{\mathrm{g}}{\mathrm{mol}}\right)} = \left(2.40 \frac{\mathrm{g}}{\mathrm{m}}\right)\left(\frac{1 \mathrm{~m}}{10^{-} \mathrm{~}}\right) \times \left(\frac{1 \mathrm{mol}}{116.86 \mathrm{g}}\right)$

STEP 3

Now, we can cancel out the units that appear in both the numerator and the denominator.
$\left(2.40 \frac{\mathrm{g}}{\cancel{\mathrm{m}}}\right)\left(\frac{1 \cancel{\mathrm{~m}}}{10^{-3} \mathrm{~}}\right) \times \left(\frac{1 \mathrm{mol}}{116.86 \cancel{\mathrm{g}}}\right) =2.40 \frac{1}{10^{-3} \mathrm{~}} \times \frac{1 \mathrm{mol}}{116.86}$

STEP 4

Next, we can simplify the expression by multiplying the numbers.
$2.40 \times \frac{1}{10^{-3}} \times \frac{1}{116.86} \mathrm{mol/L}$

STEP 5

Calculate the final value.
$\frac{2.40}{10^{-3}} \times \frac{1}{116.86} =20.48 \mathrm{mol/L}$ So, the result of the given expression is $20.48 \mathrm{mol/L}$ .

Was this helpful?

Get Studdy

Scan QR code with your device to get Studdy on iOS or Android

QR code

Studdy solves anything!

Download the app

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Parents Influencer program Contact Policy Terms