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Math  /  Algebra

Question2. 4. What is the conductance of a 39Ω39 \Omega resistor? Ans. 25,6 mS.

Studdy Solution

STEP 1

1. Conductance is the reciprocal of resistance.
2. The resistance given is 39 Ω 39 \, \Omega .
3. Conductance is measured in siemens (S), and the answer should be provided in millisiemens (mS).

STEP 2

1. Understand the relationship between conductance and resistance.
2. Calculate the conductance using the given resistance.
3. Convert the conductance from siemens to millisiemens.

STEP 3

Understand the relationship between conductance and resistance. Conductance (G G ) is the reciprocal of resistance (R R ):
G=1R G = \frac{1}{R}

STEP 4

Calculate the conductance using the given resistance. Given R=39 Ω R = 39 \, \Omega , substitute into the formula:
G=139 G = \frac{1}{39}

STEP 5

Perform the division to find the conductance in siemens:
G=139≈0.02564 S G = \frac{1}{39} \approx 0.02564 \, \text{S}

STEP 6

Convert the conductance from siemens to millisiemens. Since 1 S=1000 mS 1 \, \text{S} = 1000 \, \text{mS} :
G=0.02564 S×1000 mS/S=25.64 mS G = 0.02564 \, \text{S} \times 1000 \, \text{mS/S} = 25.64 \, \text{mS}
The conductance of a 39 Ω 39 \, \Omega resistor is approximately:
25.64 mS \boxed{25.64 \, \text{mS}}

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