Math  /  Algebra

Question2. (1 point) Debbie gathered the following evidence. 4(33)=1324(33)=132 5(33)=1655(33)=165 6(33)=1986(33)=198 Which conjecture, if any, is Debbie most likely to make from this evidence? a. When you multiply a two-digit number by 33 , the first and last digits of the product form a number that is twice the original number. b. When you multiply a one-digit number by 33 , the first and last digits of the product form a number that is three times the original number. c. When you multiply a one-digit number by 33 , the sum of the digits in the product is equal to the original number. d. None of the above conjectures can be made from this evidence.

Studdy Solution

STEP 1

1. Debbie is examining the results of multiplying a one-digit number by 33.
2. We are looking for a pattern or conjecture based on the products given.
3. The conjecture should be consistent with all provided evidence.

STEP 2

1. Analyze the given products.
2. Evaluate each conjecture option.
3. Determine which conjecture, if any, matches the evidence.

STEP 3

Analyze the given products:
1. 4×33=132 4 \times 33 = 132
2. 5×33=165 5 \times 33 = 165
3. 6×33=198 6 \times 33 = 198

STEP 4

Evaluate each conjecture option:
a. When you multiply a two-digit number by 33, the first and last digits of the product form a number that is twice the original number.
- Check for 4×33=132 4 \times 33 = 132 : First and last digits form 12, which is not twice 4. - Check for 5×33=165 5 \times 33 = 165 : First and last digits form 15, which is not twice 5. - Check for 6×33=198 6 \times 33 = 198 : First and last digits form 18, which is not twice 6. - This conjecture does not hold for any case.
b. When you multiply a one-digit number by 33, the first and last digits of the product form a number that is three times the original number.
- Check for 4×33=132 4 \times 33 = 132 : First and last digits form 12, which is not three times 4. - Check for 5×33=165 5 \times 33 = 165 : First and last digits form 15, which is three times 5. - Check for 6×33=198 6 \times 33 = 198 : First and last digits form 18, which is three times 6. - This conjecture holds for two cases.
c. When you multiply a one-digit number by 33, the sum of the digits in the product is equal to the original number.
- Check for 4×33=132 4 \times 33 = 132 : Sum of digits is 1+3+2=6 1 + 3 + 2 = 6 , which is not 4. - Check for 5×33=165 5 \times 33 = 165 : Sum of digits is 1+6+5=12 1 + 6 + 5 = 12 , which is not 5. - Check for 6×33=198 6 \times 33 = 198 : Sum of digits is 1+9+8=18 1 + 9 + 8 = 18 , which is not 6. - This conjecture does not hold for any case.

STEP 5

Determine which conjecture, if any, matches the evidence:
- Conjecture b holds for two out of three cases, which is more than any other option. - Conjecture a and c do not hold for any cases. - Therefore, the most likely conjecture Debbie might make is b.
Debbie is most likely to make conjecture b \boxed{b} .

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