Math  /  Trigonometry

Question19. Given the function below, find the 5 points amplitude. (The same function will be used for problems 19-22). y=2sin(4xπ4)+5y=2 \sin \left(4 x-\frac{\pi}{4}\right)+5 A. Amp. =5=5 B. Amp. =4=4 C. Amp. =2=2 D. Amp. =π4=\frac{\pi}{4} AA B C D

Studdy Solution

STEP 1

1. The function given is in the form y=Asin(BxC)+D y = A \sin(Bx - C) + D .
2. The amplitude of a sine function is determined by the coefficient A A in front of the sine term.

STEP 2

1. Identify the coefficient of the sine function.
2. Determine the amplitude from the coefficient.

STEP 3

Identify the coefficient of the sine function in the given equation:
The function is given as y=2sin(4xπ4)+5 y = 2 \sin \left(4x - \frac{\pi}{4}\right) + 5 .
The coefficient A A in front of the sine function is 2 2 .

STEP 4

Determine the amplitude from the coefficient:
The amplitude of a sine function y=Asin(BxC)+D y = A \sin(Bx - C) + D is the absolute value of the coefficient A A .
Therefore, the amplitude is:
Amplitude=2=2 \text{Amplitude} = |2| = 2
The amplitude of the function is 2 \boxed{2} .

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord