Math  /  Algebra

Question15 one Dicit DivisoRs The teacher worked a total of 68 hours one school week (five days). She worked the same amount of time every day except for Thursday when she worked extra (your remainder). How many hours did she work each day? How many hours did she work Thursday?

Studdy Solution

STEP 1

1. The teacher worked a total of 68 hours over five days.
2. She worked the same amount of time every day except for Thursday.
3. On Thursday, she worked extra hours, which is the remainder when dividing the total hours by five.
4. We need to find out how many hours she worked each day and how many hours she worked on Thursday.

STEP 2

1. Calculate the average number of hours worked per day.
2. Determine the remainder when dividing the total hours by five.
3. Calculate the number of hours worked each day.
4. Calculate the number of hours worked on Thursday.

STEP 3

Calculate the average number of hours worked per day.
Divide the total hours by the number of days:
Average hours per day=685 \text{Average hours per day} = \frac{68}{5}

STEP 4

Determine the remainder when dividing the total hours by five.
Perform the division 68÷5 68 \div 5 to find the quotient and remainder:
68÷5=13 remainder 3 68 \div 5 = 13 \text{ remainder } 3

STEP 5

Calculate the number of hours worked each day.
Since the teacher worked the same amount of time every day except for Thursday, she worked 13 hours on Monday, Tuesday, Wednesday, and Friday.

STEP 6

Calculate the number of hours worked on Thursday.
On Thursday, she worked the average number of hours plus the remainder:
Thursday hours=13+3=16 \text{Thursday hours} = 13 + 3 = 16
The teacher worked 13 hours each day from Monday to Wednesday and on Friday, and she worked 16 hours on Thursday.

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