Math  /  Algebra

Question14. A jar contains equal numbers of nickels and dimes. The total value of the coins is $4.05\$ 4.05. How many coins are in the jar?

Studdy Solution

STEP 1

What is this asking? If a jar has the same number of nickels ($0.05\$0.05) and dimes ($0.10\$0.10), and all the coins are worth $4.05\$4.05, how many coins are there in total? Watch out! Don't forget that the question asks for the *total* number of coins, not just the number of nickels or dimes!

STEP 2

1. Calculate the value of one nickel and one dime.
2. Determine the value of a pair of coins.
3. Calculate how many pairs of coins are in the jar.
4. Calculate the total number of coins.

STEP 3

A nickel is worth $0.05\$0.05.
A dime is worth $0.10\$0.10.
Easy peasy!

STEP 4

Since we have an equal number of nickels and dimes, let's think about them in *pairs*.
One nickel plus one dime equals $0.05+$0.10=$0.15\$0.05 + \$0.10 = \$0.15.
So, each **pair** of coins is worth $0.15\$0.15.

STEP 5

The total value of all the coins is $4.05\$4.05.
Since each pair is worth $0.15\$0.15, we can figure out how many pairs are in the jar by dividing the total value by the value of one pair: $4.05$0.15=40515=27 \frac{\$4.05}{\$0.15} = \frac{405}{15} = 27 There are **27 pairs** of coins in the jar!

STEP 6

Each pair contains two coins (one nickel and one dime).
Since we have 27 pairs, the total number of coins is 272=5427 \cdot 2 = 54.
Boom!

STEP 7

There are **54** coins in the jar.

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