Math  /  Trigonometry

Question12. How many different sinusoidal functions can be written that have a period of 3π3 \pi, an amplitude of 1 , and a minimum at (2,3)(2,3) ? [1 mark]

Studdy Solution

STEP 1

1. The sinusoidal function is of the form y=asin(bx+c)+d y = a \sin(bx + c) + d or y=acos(bx+c)+d y = a \cos(bx + c) + d .
2. The period of the function is 3π 3\pi .
3. The amplitude of the function is 1 1 .
4. The function has a minimum at the point (2,3) (2, 3) .

STEP 2

1. Determine the general form of the sinusoidal function.
2. Use the given period to find the value of b b .
3. Use the given amplitude to determine a a .
4. Use the minimum point to find c c and d d .
5. Count the number of different sinusoidal functions that satisfy these conditions.

STEP 3

Determine the general form of the sinusoidal function. Since the amplitude is 1, we have:
y=sin(bx+c)+dory=cos(bx+c)+d y = \sin(bx + c) + d \quad \text{or} \quad y = \cos(bx + c) + d

STEP 4

Use the given period to find b b . The period T T is given by:
T=2πb T = \frac{2\pi}{|b|}
Given T=3π T = 3\pi , solve for b b :
3π=2πb 3\pi = \frac{2\pi}{|b|} b=23 |b| = \frac{2}{3}

STEP 5

Use the given amplitude to determine a a . Since the amplitude is 1, we have:
a=1 |a| = 1
Thus, a=1 a = 1 or a=1 a = -1 .

STEP 6

Use the minimum point to find c c and d d . The minimum at (2,3) (2, 3) implies:
For y=sin(bx+c)+d y = \sin(bx + c) + d :
sin(b2+c)=1andd=4 \sin(b \cdot 2 + c) = -1 \quad \text{and} \quad d = 4
For y=cos(bx+c)+d y = \cos(bx + c) + d :
cos(b2+c)=1andd=4 \cos(b \cdot 2 + c) = -1 \quad \text{and} \quad d = 4
Determine c c for each case:
For sin \sin , b2+c=3π2+2kπ b \cdot 2 + c = \frac{3\pi}{2} + 2k\pi for integer k k .
For cos \cos , b2+c=π+2kπ b \cdot 2 + c = \pi + 2k\pi for integer k k .

STEP 7

Count the number of different sinusoidal functions. Each choice of a a and each integer k k gives a different function. Since a=1 a = 1 or a=1 a = -1 , and k k can be any integer, there are infinitely many functions.
The number of different sinusoidal functions is:
\boxed{\infty}

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