Math  /  Algebra

Question(129i)+(326i)=(12-9 i)+(32-6 i)= \square Express your answer in the form (a+bi)(a+b i).

Studdy Solution

STEP 1

What is this asking? We're adding two *complex numbers* and need to write the result in the standard form a+bia+bi. Watch out! Don't mix up the real and imaginary parts!

STEP 2

1. Group the real and imaginary terms
2. Add the real parts
3. Add the imaginary parts
4. Combine the results

STEP 3

Let's **rewrite** our expression to **group** the real parts and the imaginary parts together.
This makes it super clear what we need to add!
Remember, the *real part* is the number *without* the ii, and the *imaginary part* is the number *with* the ii.
So, we have: (129i)+(326i)=(12+32)+(9i6i)(12-9i) + (32-6i) = (12+32) + (-9i-6i)

STEP 4

Now, let's **add** those real parts together!
We have 1212 and 3232, and when we add them, we get: 12+32=4412 + 32 = 44 So, our **new real part** is 4444!

STEP 5

Next up, the imaginary parts!
We have 9i-9i and 6i-6i.
When we add these together, we get: 9i+(6i)=15i-9i + (-6i) = -15i Our **new imaginary part** is 15i-15i!

STEP 6

Finally, let's **put it all together**!
We have our **real part**, which is 4444, and our **imaginary part**, which is 15i-15i.
We write the **final answer** in the form a+bia + bi, so we get: 44+(15i)=4415i44 + (-15i) = 44 - 15i

STEP 7

4415i44-15i

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