Math  /  Algebra

Question11. Find the value of xx. xlog27=7x^{\log _{2} 7}=7

Studdy Solution

STEP 1

1. The equation xlog27=7 x^{\log_{2} 7} = 7 involves an exponential expression with a logarithmic exponent.
2. We will use properties of logarithms and exponents to solve for x x .

STEP 2

1. Recognize the form of the equation and apply logarithmic properties.
2. Solve for x x .

STEP 3

Recognize that the equation xlog27=7 x^{\log_{2} 7} = 7 can be approached by taking the logarithm of both sides. Use the property of logarithms that allows us to bring the exponent down as a coefficient:
Take the logarithm base 2 of both sides:
log2(xlog27)=log2(7) \log_{2}(x^{\log_{2} 7}) = \log_{2}(7)
Apply the power rule of logarithms:
log27log2x=log27 \log_{2} 7 \cdot \log_{2} x = \log_{2} 7

STEP 4

Since log27 \log_{2} 7 is a common factor on both sides, divide both sides by log27 \log_{2} 7 to isolate log2x \log_{2} x :
log2x=1 \log_{2} x = 1
Convert the logarithmic equation to its exponential form to solve for x x :
x=21 x = 2^1
x=2 x = 2
The value of x x is:
2 \boxed{2}

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