Math / Numbers & Operations

Question10. Luisa wants to use place-value blocks to show $367+215$ . How many tens blocks will she need to show the sum by regrouping?
A 9 B. 8
C 7 D 6

Studdy Solution

STEP 1

1. Luisa is using place-value blocks to represent numbers.
2. The numbers $367$ and $215$ need to be added.
3. Place-value blocks include hundreds, tens, and ones blocks.
4. We need to determine how many tens blocks are required after regrouping.

STEP 2

1. Add the numbers without regrouping.
2. Determine the number of tens blocks needed.
3. Regroup if necessary and find the final number of tens blocks.

STEP 3

Add the numbers $367$ and $215$ without considering regrouping initially.
$367 + 215 = 582$

STEP 4

Identify the number of tens in the sum $582$ .
The number $582$ can be broken down into: - Hundreds: $5$ - Tens: $8$ - Ones: $2$

STEP 5

Since the tens digit in $582$ is $8$ , Luisa will need $8$ tens blocks to represent the sum after regrouping.
The correct answer is:
$\boxed{8}$

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Question10. Luisa wants to use place-value blocks to show $367+215$ . How many tens blocks will she need to show the sum by regrouping?
A 9 B. 8
C 7 D 6

Studdy Solution

STEP 1

1. Luisa is using place-value blocks to represent numbers.
2. The numbers $367$ and $215$ need to be added.
3. Place-value blocks include hundreds, tens, and ones blocks.
4. We need to determine how many tens blocks are required after regrouping.

STEP 2

1. Add the numbers without regrouping.
2. Determine the number of tens blocks needed.
3. Regroup if necessary and find the final number of tens blocks.

STEP 3

Add the numbers $367$ and $215$ without considering regrouping initially.
$367 + 215 = 582$

STEP 4

Identify the number of tens in the sum $582$ .
The number $582$ can be broken down into: - Hundreds: $5$ - Tens: $8$ - Ones: $2$

STEP 5

Since the tens digit in $582$ is $8$ , Luisa will need $8$ tens blocks to represent the sum after regrouping.
The correct answer is:
$\boxed{8}$

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Question10. Luisa wants to use place-value blocks to show 367+215367+215367+215. How many tens blocks will she need to show the sum by regrouping?A 9 B. 8C 7 D 6

Studdy Solution

STEP 1

1. Luisa is using place-value blocks to represent numbers.2. The numbers 367 367 367 and 215 215 215 need to be added.3. Place-value blocks include hundreds, tens, and ones blocks.4. We need to determine how many tens blocks are required after regrouping.

STEP 2

1. Add the numbers without regrouping.2. Determine the number of tens blocks needed.3. Regroup if necessary and find the final number of tens blocks.

STEP 3

Add the numbers 367 367 367 and 215 215 215 without considering regrouping initially.367+215=582367 + 215 = 582367+215=582

STEP 4

Identify the number of tens in the sum 582 582 582.The number 582 582 582 can be broken down into: - Hundreds: 5 5 5 - Tens: 8 8 8 - Ones: 2 2 2

STEP 5

Since the tens digit in 582 582 582 is 8 8 8, Luisa will need 8 8 8 tens blocks to represent the sum after regrouping. The correct answer is:8\boxed{8}8​

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Question10. Luisa wants to use place-value blocks to show $367+215$ . How many tens blocks will she need to show the sum by regrouping?
A 9 B. 8
C 7 D 6

1. Luisa is using place-value blocks to represent numbers.
2. The numbers $367$ and $215$ need to be added.
3. Place-value blocks include hundreds, tens, and ones blocks.
4. We need to determine how many tens blocks are required after regrouping.

1. Add the numbers without regrouping.
2. Determine the number of tens blocks needed.
3. Regroup if necessary and find the final number of tens blocks.

Add the numbers $367$ and $215$ without considering regrouping initially.
$367 + 215 = 582$

Identify the number of tens in the sum $582$ .
The number $582$ can be broken down into: - Hundreds: $5$ - Tens: $8$ - Ones: $2$

Since the tens digit in $582$ is $8$ , Luisa will need $8$ tens blocks to represent the sum after regrouping.
The correct answer is:
$\boxed{8}$