Math / Algebra

Question1. $y=x+7$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & & \\ \hline 0 & & & \\ \hline 2 & & & \\ \hline 4 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to find the $y$ values for some given $x$ values using the equation $y = x + 7$ , and then write the coordinate pairs. Watch out! Make sure to add correctly, especially with negative numbers!

STEP 2

1. Find y when x = -1
2. Find y when x = 0
3. Find y when x = 2
4. Find y when x = 4

STEP 3

Let's kick things off with $x = -1$ .
We'll substitute this value into our equation: $y = x + 7$ .

STEP 4

So, $y = (-1) + 7$ .
Remember, adding a positive 7 to a negative 1 is the same as adding to zero, then adding the rest: $(-1) + 1 + 6 = 0 + 6 = 6$ .
Therefore, $y = \mathbf{6}$ .
This gives us the point $(-1, 6)$ .
Awesome!

STEP 5

Next up, $x = 0$ !
Substituting into $y = x + 7$ , we get $y = 0 + 7$ .

STEP 6

Well, adding zero to anything doesn't change its value!
So, $y = \mathbf{7}$ .
Our coordinate pair is $(0, 7)$ .
Keep it up!

STEP 7

Now, let's tackle $x = 2$ .
Plugging it into $y = x + 7$ , we have $y = 2 + 7$ .

STEP 8

Adding those together gives us $y = \mathbf{9}$ .
That means our point is $(2, 9)$ .
Fantastic!

STEP 9

Finally, we have $x = 4$ .
Substituting into $y = x + 7$ , we get $y = 4 + 7$ .

STEP 10

Adding 4 and 7 gives us $y = \mathbf{11}$ .
So, our final coordinate pair is $(4, 11)$ .
We did it!

STEP 11

\begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & 6 & (-1, 6) \\ \hline 0 & & 7 & (0, 7) \\ \hline 2 & & 9 & (2, 9) \\ \hline 4 & & 11 & (4, 11) \\ \hline \end{tabular}

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Question1. $y=x+7$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & & \\ \hline 0 & & & \\ \hline 2 & & & \\ \hline 4 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to find the $y$ values for some given $x$ values using the equation $y = x + 7$ , and then write the coordinate pairs. Watch out! Make sure to add correctly, especially with negative numbers!

STEP 2

1. Find y when x = -1
2. Find y when x = 0
3. Find y when x = 2
4. Find y when x = 4

STEP 3

Let's kick things off with $x = -1$ .
We'll substitute this value into our equation: $y = x + 7$ .

STEP 4

So, $y = (-1) + 7$ .
Remember, adding a positive 7 to a negative 1 is the same as adding to zero, then adding the rest: $(-1) + 1 + 6 = 0 + 6 = 6$ .
Therefore, $y = \mathbf{6}$ .
This gives us the point $(-1, 6)$ .
Awesome!

STEP 5

Next up, $x = 0$ !
Substituting into $y = x + 7$ , we get $y = 0 + 7$ .

STEP 6

Well, adding zero to anything doesn't change its value!
So, $y = \mathbf{7}$ .
Our coordinate pair is $(0, 7)$ .
Keep it up!

STEP 7

Now, let's tackle $x = 2$ .
Plugging it into $y = x + 7$ , we have $y = 2 + 7$ .

STEP 8

Adding those together gives us $y = \mathbf{9}$ .
That means our point is $(2, 9)$ .
Fantastic!

STEP 9

Finally, we have $x = 4$ .
Substituting into $y = x + 7$ , we get $y = 4 + 7$ .

STEP 10

Adding 4 and 7 gives us $y = \mathbf{11}$ .
So, our final coordinate pair is $(4, 11)$ .
We did it!

STEP 11

\begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & 6 & (-1, 6) \\ \hline 0 & & 7 & (0, 7) \\ \hline 2 & & 9 & (2, 9) \\ \hline 4 & & 11 & (4, 11) \\ \hline \end{tabular}

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Question1. y=x+7y=x+7y=x+7 \begin{tabular}{|c|l|c|c|} \hlinexxx & & yyy & (x,y)(x, y)(x,y) \\ \hline-1 & & & \\ \hline 0 & & & \\ \hline 2 & & & \\ \hline 4 & & & \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to find the yyy values for some given xxx values using the equation y=x+7y = x + 7y=x+7, and then write the coordinate pairs. Watch out! Make sure to add correctly, especially with negative numbers!

STEP 2

1. Find y when x = -12. Find y when x = 03. Find y when x = 24. Find y when x = 4

STEP 3

Let's **kick things off** with x=−1x = -1x=−1.We'll **substitute** this value into our equation: y=x+7y = x + 7y=x+7.

STEP 4

So, y=(−1)+7y = (-1) + 7y=(−1)+7.Remember, adding a positive 7 to a negative 1 is the same as adding to zero, then adding the rest: (−1)+1+6=0+6=6(-1) + 1 + 6 = 0 + 6 = 6(−1)+1+6=0+6=6.Therefore, y=6y = \mathbf{6}y=6.This gives us the point (−1,6)(-1, 6)(−1,6).Awesome!

STEP 5

Next up, x=0x = 0x=0!Substituting into y=x+7y = x + 7y=x+7, we get y=0+7y = 0 + 7y=0+7.

STEP 6

Well, adding zero to anything doesn't change its value!So, y=7y = \mathbf{7}y=7.Our coordinate pair is (0,7)(0, 7)(0,7).Keep it up!

STEP 7

Now, let's **tackle** x=2x = 2x=2.Plugging it into y=x+7y = x + 7y=x+7, we have y=2+7y = 2 + 7y=2+7.

STEP 8

Adding those together gives us y=9y = \mathbf{9}y=9.That means our point is (2,9)(2, 9)(2,9).Fantastic!

STEP 9

Finally, we have x=4x = 4x=4.Substituting into y=x+7y = x + 7y=x+7, we get y=4+7y = 4 + 7y=4+7.

STEP 10

Adding 4 and 7 gives us y=11y = \mathbf{11}y=11.So, our final coordinate pair is (4,11)(4, 11)(4,11).We did it!

STEP 11

\begin{tabular}{|c|l|c|c|} \hlinexxx & & yyy & (x,y)(x, y)(x,y) \\ \hline-1 & & 6 & (-1, 6) \\ \hline 0 & & 7 & (0, 7) \\ \hline 2 & & 9 & (2, 9) \\ \hline 4 & & 11 & (4, 11) \\ \hline \end{tabular}

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Question1. $y=x+7$ \begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & & \\ \hline 0 & & & \\ \hline 2 & & & \\ \hline 4 & & & \\ \hline \end{tabular}

What is this asking? We need to find the $y$ values for some given $x$ values using the equation $y = x + 7$ , and then write the coordinate pairs. Watch out! Make sure to add correctly, especially with negative numbers!

1. Find y when x = -1
2. Find y when x = 0
3. Find y when x = 2
4. Find y when x = 4

Let's kick things off with $x = -1$ .
We'll substitute this value into our equation: $y = x + 7$ .

So, $y = (-1) + 7$ .
Remember, adding a positive 7 to a negative 1 is the same as adding to zero, then adding the rest: $(-1) + 1 + 6 = 0 + 6 = 6$ .
Therefore, $y = \mathbf{6}$ .
This gives us the point $(-1, 6)$ .
Awesome!

Next up, $x = 0$ !
Substituting into $y = x + 7$ , we get $y = 0 + 7$ .

Well, adding zero to anything doesn't change its value!
So, $y = \mathbf{7}$ .
Our coordinate pair is $(0, 7)$ .
Keep it up!

Now, let's tackle $x = 2$ .
Plugging it into $y = x + 7$ , we have $y = 2 + 7$ .

Adding those together gives us $y = \mathbf{9}$ .
That means our point is $(2, 9)$ .
Fantastic!

Finally, we have $x = 4$ .
Substituting into $y = x + 7$ , we get $y = 4 + 7$ .

Adding 4 and 7 gives us $y = \mathbf{11}$ .
So, our final coordinate pair is $(4, 11)$ .
We did it!

\begin{tabular}{|c|l|c|c|} \hline $x$ & & $y$ & $(x, y)$ \\ \hline-1 & & 6 & (-1, 6) \\ \hline 0 & & 7 & (0, 7) \\ \hline 2 & & 9 & (2, 9) \\ \hline 4 & & 11 & (4, 11) \\ \hline \end{tabular}