QuestionFind the pot of gold at the end of the rainbow:
1. $(4-2) \times 4$
2. $+5-7$
3. $\times(4-3)$

Studdy Solution

STEP 1

Assumptions1. The operations in the problem are carried out from left to right. . The operations inside the parentheses are carried out first, according to the order of operations (also known as BIDMAS/BODMAS/PEDMAS).

STEP 2

First, we need to carry out the operations inside the parentheses. For the first equation, this means calculating $(4-2)$ .
$(4-2) =2$

STEP 3

Next, we multiply the result from the previous step by.
$2 \times =8$

STEP 4

Now, we add to the result from the previous step.
$8 + =13$

STEP 5

Subtract7 from the result from the previous step.
$13 -7 =$

STEP 6

Next, we need to carry out the operation inside the parentheses for the third equation, which means calculating $(4-3)$ .
$(4-3) =1$

STEP 7

Finally, we multiply the result from step5 by the result from step6.
$6 \times1 =6$ The pot of gold at the end of the rainbow is6.

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QuestionFind the pot of gold at the end of the rainbow:
1. $(4-2) \times 4$
2. $+5-7$
3. $\times(4-3)$

Studdy Solution

STEP 1

Assumptions1. The operations in the problem are carried out from left to right. . The operations inside the parentheses are carried out first, according to the order of operations (also known as BIDMAS/BODMAS/PEDMAS).

STEP 2

First, we need to carry out the operations inside the parentheses. For the first equation, this means calculating $(4-2)$ .
$(4-2) =2$

STEP 3

Next, we multiply the result from the previous step by.
$2 \times =8$

STEP 4

Now, we add to the result from the previous step.
$8 + =13$

STEP 5

Subtract7 from the result from the previous step.
$13 -7 =$

STEP 6

Next, we need to carry out the operation inside the parentheses for the third equation, which means calculating $(4-3)$ .
$(4-3) =1$

STEP 7

Finally, we multiply the result from step5 by the result from step6.
$6 \times1 =6$ The pot of gold at the end of the rainbow is6.

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QuestionFind the pot of gold at the end of the rainbow: 1. (4−2)×4(4-2) \times 4(4−2)×4 2. +5−7+5-7+5−7 3. ×(4−3)\times(4-3)×(4−3)

Studdy Solution

STEP 1

Assumptions1. The operations in the problem are carried out from left to right. . The operations inside the parentheses are carried out first, according to the order of operations (also known as BIDMAS/BODMAS/PEDMAS).

STEP 2

First, we need to carry out the operations inside the parentheses. For the first equation, this means calculating (4−2)(4-2)(4−2).(4−2)=2 (4-2) =2 (4−2)=2

STEP 3

Next, we multiply the result from the previous step by.2×=82 \times =8 2×=8

STEP 4

Now, we add to the result from the previous step.8+=138 + =13 8+=13

STEP 5

Subtract7 from the result from the previous step.13−7=13 -7 = 13−7=

STEP 6

Next, we need to carry out the operation inside the parentheses for the third equation, which means calculating (4−3)(4-3)(4−3).(4−3)=1 (4-3) =1 (4−3)=1

STEP 7

Finally, we multiply the result from step5 by the result from step6.6×1=66 \times1 =6 6×1=6The pot of gold at the end of the rainbow is6.

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind the pot of gold at the end of the rainbow:
1. $(4-2) \times 4$
2. $+5-7$
3. $\times(4-3)$

First, we need to carry out the operations inside the parentheses. For the first equation, this means calculating $(4-2)$ .
$(4-2) =2$

Next, we multiply the result from the previous step by.
$2 \times =8$

Now, we add to the result from the previous step.
$8 + =13$

Subtract7 from the result from the previous step.
$13 -7 =$

Next, we need to carry out the operation inside the parentheses for the third equation, which means calculating $(4-3)$ .
$(4-3) =1$

Finally, we multiply the result from step5 by the result from step6.
$6 \times1 =6$ The pot of gold at the end of the rainbow is6.