QuestionDivide 18 by 153.

Studdy Solution

STEP 1

Assumptions1. We are performing a long division operation. . The divisor is18.
3. The dividend is153.

STEP 2

First, we need to determine how many times the divisor (18) goes into the first digit or digits of the dividend (153).In this case,18 does not go into1 (the first digit of153), so we consider the first two digits (15).
$18 \, \text{into} \,15$

STEP 3

Since18 is larger than15, we then consider the first three digits (153).
$18 \, \text{into} \,153$

STEP 4

We find that18 goes into153 eight times. So,8 is the first digit of the quotient.
$\text{Quotient} =8$

STEP 5

Next, we multiply the divisor (18) by the first digit of the quotient (8) and subtract the result from the dividend (153).
$\text{Remainder} =153 - (18 \times8)$

STEP 6

Calculate the remainder.
$\text{Remainder} =153 - (18 \times8) =153 -144 =9$

STEP 7

Since there are no more digits in the dividend, we conclude that9 is the remainder.
$\text{Remainder} =9$ The result of the division is with a remainder of9.

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